3.8 kPa
If the number of moles of gas decreases, the volume of the gas will decrease as well, assuming constant temperature and pressure. This is described by Boyle's Law, which states that the volume of a gas is inversely proportional to the number of moles of gas when pressure and temperature are held constant.
we first find the number of moles( number of moles= mass/molar mass). the we can find the volume by using the formule( volume=number of moles multiplyd by the molar volume)
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
At STP, 1 mole of gas occupies a volume of 22.4 liters. Thus, 4/5 moles of gas will occupy .8*22.4 liters.
Yes. Since pressure and volume are inversely related, volume decreases when pressure increases (as long as temperature is constant). Consider the equation: PV=nRT, where n = moles, T is in degrees Kelvin, and R is the gas constant 0.082. Do the algebra and see how: P=nRT/V and the inverses become more easily understood.
If the number of moles of gas decreases, the volume of the gas will decrease as well, assuming constant temperature and pressure. This is described by Boyle's Law, which states that the volume of a gas is inversely proportional to the number of moles of gas when pressure and temperature are held constant.
The volume that 2.4 moles of chlorine gas would occupy depends on the temperature and pressure of the gas, according to the ideal gas law (PV = nRT). At standard temperature and pressure (STP), which is 0°C and 1 atm pressure, 2.4 moles of chlorine gas would occupy approximately 53.75 liters.
This volume is 79,79 litres.
The volume is approx. 15,35 litres.
we first find the number of moles( number of moles= mass/molar mass). the we can find the volume by using the formule( volume=number of moles multiplyd by the molar volume)
The ideal gas law equation, w-nRT, describes the relationship between temperature (T), volume (V), pressure (P), and the number of moles of a gas (n). It states that the product of pressure and volume is directly proportional to the product of the number of moles, the gas constant (R), and the temperature. In simpler terms, as temperature increases, the volume of a gas increases if pressure and the number of moles are constant. Similarly, if pressure increases, volume decreases if temperature and the number of moles are constant.
Approx. 774 litres.
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
At STP, 1 mole of gas occupies a volume of 22.4 liters. Thus, 4/5 moles of gas will occupy .8*22.4 liters.
What you need to know to work this out is that:- Moles of gases at standard temperature pressure (With P and T constant) are proportional to the volume they occupy, divided by their specific gas constant.
The formula you need to remember is PV = nrT (and this is a closed system). P = pressure, V = Volume, n = moles of gas, r is a constant and T = temperature. So if the volume decreases, the pressure must increase in order for the equation to remain balanced. Plug some fake numbers in if that helps. Just remember that PV has to equal nrT
Using the ideal gas law, V = (nRT)/P, where V is volume, n is moles, R is the gas constant, T is temperature in Kelvin, and P is pressure, we can calculate the volume to be 7.34 L.