20 degree c\
The heat of vaporization of water is 40.79 kJ/mol. First, determine the number of moles in 24.40 grams of water. Then, convert moles to joules using the molar heat of vaporization. This will give you the amount of heat needed to vaporize 24.40 grams of water.
To calculate the number of joules of heat gained by water, you can use the formula Q = m * c * ΔT, where Q is the heat gained, m is the mass of water in grams, c is the specific heat capacity of water (4.18 J/g°C), and ΔT is the change in temperature in degrees Celsius. Plug in the values for m, c, and ΔT to calculate the heat gained in joules.
To calculate the volume of water (H2O) needed for a specific experiment, you can use the formula: Volume Mass / Density. First, determine the mass of water required for the experiment. Then, find the density of water, which is approximately 1 gram per milliliter. Divide the mass by the density to calculate the volume of water needed.
To calculate the heat change, you need to use the formula: q = mcΔT. First, calculate the specific heat capacity of water (4.18 J/g°C). Then calculate the change in temperature (60°C - 25.5°C). Finally, substitute these values into the formula along with the mass of water (55.0g) to find the heat change in joules.
Q = [ mI ] [ h sub sf + CshW ( 100.0 C - 0.0 C ) + h sub fg ]Q = [ 25 g ] [ 333.7 J /g + ( 4.184 J / g - C ) ( 100.0 C ) + 2257 J / g ]Q = [ 25 g ] [ 3009.1 J / g ] = 75230 J
To calculate the joules needed to raise the temperature of water, you can use the formula Q = mcΔT, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. First, calculate the mass of 2.0 liters of water in grams (1 mL of water = 1g), then use the specific heat capacity of water (4.18 J/g°C) to find the total heat energy required. The final step is to calculate the joules needed using the formula, remembering that 1 calorie is equivalent to 4.18 joules.
2,26 Kj are necessary
100oC
100oC
Water melts at 0oC, and boils at 100oC.
It takes 4.184 joules of energy to change the temperature of 1 gram of water by 1 degree Celsius.
100oC or 373.15K
9.1x10^2J
The necessary heat is 9,22 joules.
No! Water boils at 100oC, silly!
Pure water boils at 100oC (212oF)
Temperature of water should be around 100oC.