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What is the molarity of an aqueous solution containing 40 g of glucose in 1.5 l of solution?

To find the molarity, first calculate the number of moles of glucose in 40 g using its molar mass. Then, divide the moles of glucose by the volume of the solution in liters (1.5 L) to get the molarity.


What is the osmolarity of 50mM of glucose?

To calculate the osmolarity of a solution containing 50mM of glucose, you'll need to consider the number of particles in solution. Glucose does not dissociate into multiple particles in solution, so its osmolarity is equivalent to its molarity. Therefore, the osmolarity of a 50mM glucose solution would be 50 mOsm/L.


How much 80 g of glucose C6H12O6 is added to enough water to make 750ml of sugar solution What is the molarity?

To find the molarity of the sugar solution, we first need to convert the mass of glucose to moles. The molar mass of glucose (C6H12O6) is 180 g/mol. So, 80 g of glucose is equal to 80/180 = 0.444 moles. Next, calculate the molarity by dividing moles of glucose by liters of solution (0.75 L), Molarity = 0.444 moles / 0.75 L = 0.592 M.


What is the morality of a solution that has 3 mol of glucose in 6kg of water?

The molarity of a solution with 3 mol of glucose in 6 kg of water cannot be determined without knowing the volume of the solution. Molarity is defined as the amount of solute (in mol) divided by the volume of the solution in liters. Without the volume, the molarity of the solution cannot be calculated.


What is the molarity of a solution that has 1.5 mol of sugar in 2 l of solution?

2 moles in 2 liters means 1 mole in 1 liter - so it its molarity is 1.

Related Questions

What is the molarity of an aqueous solution containing 40 g of glucose in 1.5 l of solution?

To find the molarity, first calculate the number of moles of glucose in 40 g using its molar mass. Then, divide the moles of glucose by the volume of the solution in liters (1.5 L) to get the molarity.


What is the osmolarity of 50mM of glucose?

To calculate the osmolarity of a solution containing 50mM of glucose, you'll need to consider the number of particles in solution. Glucose does not dissociate into multiple particles in solution, so its osmolarity is equivalent to its molarity. Therefore, the osmolarity of a 50mM glucose solution would be 50 mOsm/L.


How much 80 g of glucose C6H12O6 is added to enough water to make 750ml of sugar solution What is the molarity?

To find the molarity of the sugar solution, we first need to convert the mass of glucose to moles. The molar mass of glucose (C6H12O6) is 180 g/mol. So, 80 g of glucose is equal to 80/180 = 0.444 moles. Next, calculate the molarity by dividing moles of glucose by liters of solution (0.75 L), Molarity = 0.444 moles / 0.75 L = 0.592 M.


If 154 grams of glucose are dissolved to yield one liter of solution what is the molarity of the solution?

Molarity = moles of solute/Liters of solution Find moles glucose, which is molecular formula------C6H12O6 154 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.8548 moles C6H12O6 Molarity = 0.8548 moles C6H12O6/1 Liter = 0.855 M glucose ---------------------------


What is the molarity of an aqueous solution containing 32.8 g of C6H12O6 in 1.0 L of solution?

Find moles of glucose. 32.8 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.18206 moles C6H12O6 Molarity = moles of solute/Liters of solution M = 0.18206 moles C6H12O6/1.0 L = 0.18 M C6H12O6


What is the molarity of 449 ml of solution containing 183 mmol of glucose?

To find the molarity (M) of the solution, use the formula: [ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} ] First, convert 183 mmol to moles: [ 183 , \text{mmol} = 0.183 , \text{mol} ] Next, convert 449 ml to liters: [ 449 , \text{ml} = 0.449 , \text{L} ] Now, calculate the molarity: [ \text{M} = \frac{0.183 , \text{mol}}{0.449 , \text{L}} \approx 0.408 , \text{M} ] Thus, the molarity of the solution is approximately 0.408 M.


What is the morality of a solution that has 3 mol of glucose in 6kg of water?

The molarity of a solution with 3 mol of glucose in 6 kg of water cannot be determined without knowing the volume of the solution. Molarity is defined as the amount of solute (in mol) divided by the volume of the solution in liters. Without the volume, the molarity of the solution cannot be calculated.


What is the molarity of a solution that has 1.5 mol of sugar in 2 l of solution?

2 moles in 2 liters means 1 mole in 1 liter - so it its molarity is 1.


What is the molality of a solution that has 4 mol of KCl in 0.800 kg of water A.?

4 mol over 0.800 kg


What is the molarity of a solution prepared by dissolving 15.8 g of glucose of MW 180 amu in 169 mL of solution?

The first step is to calculate the number of moles of glucose by dividing the mass (15.8 g) by the molecular weight (180 g/mol). This gives 0.088 moles of glucose. Next, calculate the volume in liters by dividing 169 mL by 1000, which gives 0.169 L. Finally, divide the moles of solute by the volume of solution in liters to get the molarity: 0.088 moles / 0.169 L = 0.52 M.


Is there a glucose shot?

Yes; the solution called "Ringer's Lactate" is a mixture containing water, essential salts and electrolytes, and glucose.


What is the osmolarity of 5.5 percent glucose solution?

To calculate the osmolarity of a 5.5% glucose solution, first convert the percentage to grams per liter: 5.5% means 5.5 grams of glucose per 100 mL, which is 55 grams per liter. Glucose (C6H12O6) has a molar mass of approximately 180 g/mol, so 55 grams corresponds to about 0.306 moles per liter (55 g / 180 g/mol). Since glucose does not dissociate in solution, the osmolarity is equal to its molarity, which is approximately 0.306 osmoles per liter.