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4.00 grams of NaOH have been added to 2.00 liters of water. The molarity of this solution is?

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How many liters of naoh are in 1.3 moles of 3.42 m of naoh?

Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters


How many moles of naoh are contained in 65.0ml of a 2.20m solution of naoh in H2O?

Moles/Liters=Molarity (M) therefore: Molarity*Liters=moles Since you were given milliliters, you must first convert your volume to liters for the equation to be accurate. 2.2M*.065L=moles=.143 moles NaOH


How many grams of solute are required to make a 918 mL solution of sodium hydroxide with a concentration of 0.4922 M?

Molarity = moles of solute/Liters of solution ( 918 ml = 0.918 liters )rearranged algebraically,moles of solute = Liters of solution * Molaritymoles of NaOH = (0.918 l)(0.4922 M)= 0.45184 moles NaOH=======================so,0.45184 moles NaOH (39.998 grams/1 mole NaOH)= 18.1 grams sodium hydroxide needed============================


How many grams of NaOH are in 350 mL of a 5.7 M NaOH solution?

Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------


How many grams of NaOH(MW40.0) are there in 400.0 ml of a 0.175 M NaOH solution?

To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.


How many moles of NaOH are needed to prepare 2 liters of a 2.0 M solution?

4 moles or 160 g NaOH is required for one litre solution.


What is the OH- in a solution that contains 0.240 g NaOH in 0.225 L of solution?

Molarity = moles solute/Liters solution get moles NaOH 0.240 grams NaOH (1 mole NaOH/39.998 grams) = 0.0060 moles NaOH ----------------------------------as one to one OH- has this many moles also Molarity = 0.0060 moles OH-/0.225 Liters = 0.0267 M OH- ----------------------- -log(0.0267 M OH-) = 14 - 1.573 = 12.4 pH -------------


How many moles of NaOH are present in 24.5 mL of 0.130 M NaOH?

Molarity = moles of solute/Liters of solution ( 24.5 mL = 0.0245 L)Rearranged,moles of solute = Liters of solution * MolarityMoles NaOH = (0.0245 L)(0.130 M NaOH)= 3.19 X 10 -3 moles NaOH==================


How many grams of NaOH would you need to make 4 litters of 8 M NaOH?

To calculate the grams of NaOH needed, use the formula: grams = molarity x volume x molar mass. First, convert the volume to liters (4 liters). Next, calculate the grams using 8 M as the molarity and the molar mass of NaOH. This will give you the amount of NaOH required to make 4 liters of 8 M NaOH solution.


How many grams of NaOH are in 750 ml 0.600 M NaOH solution?

This solution contain 26,3 g NaOH.


How many moles are in 15 mL of 2.9 M NaOH?

To determine the number of moles in a solution, you need to use the formula n = M x V, where n is the number of moles, M is the molarity, and V is the volume in liters. First, convert 15 mL to liters (15 mL = 0.015 L). Then, multiply the molarity (2.9 M) by the volume (0.015 L) to find the number of moles. n = 2.9 M x 0.015 L = 0.0435 moles.


How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?

Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.