answersLogoWhite

0

No... it orbital 2d does not exist.

User Avatar

Wiki User

16y ago

What else can I help you with?

Related Questions

Which of the orbital designation are invalid 4s 3f 2d 3d?

The orbital designations 3f and 2d are invalid. The letter "f" is not used to designate orbitals, and the numbers in the designation should follow a specific order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, etc.


What is the element 1s22s22p63s23p64s23d104p65s1?

This element is bromine (Br).


What atomic orbital designations are incorrect a7f b3f c2d d6p?

2d is incorrect


Which of the following atomic orbital designations are incorrect 7f 6p 2d 3f?

The incorrect atomic orbital designation from the list provided is 7f. The correct designations are 6p, 2d, and 3f. The main energy levels for orbitals typically range from 1 to 7, and the "f" orbitals are found starting from the 4th principal energy level.


Why there is no possibility of 2d and 3f orbitals?

The Angular Momentum Quantum number L, defines how many types of orbitals can exist. For a particular Quantum Level n, L is defined as any integer from 0 to L = n-1. For example, for the energy level n = we must have, L = 0 or 1. L=0 relates to the s-orbital L=1 relates to the p-orbital L=2 would relate to the d-orbital, but we can see here that for n=2, L cannot = 2


The following is the correct orbital configuration for nitrogen 1s22s22d3. True False?

False. The correct orbital configuration for nitrogen is 1s² 2s² 2p³. Nitrogen has a total of seven electrons, and they fill the 1s and 2s orbitals before filling the 2p orbital, not the 2d orbital, which does not apply to nitrogen.


Why dihelium does not exist?

Molecular orbitals: dihelium has two electrons in the bonding orbital and two in the antibonding orbital. That why it does not exists.


Why 2d and 2f orbitals are not possible?

The 2d and 2f orbitals are not possible because of the constraints imposed by quantum mechanics and the principal quantum number (n). The principal quantum number n specifies the energy level and size of the orbital, and for any given n, the maximum angular momentum quantum number (l) can only take values from 0 to n-1. Therefore, for n=2, l can only be 0 (s orbital) or 1 (p orbital), making the 2d and 2f orbitals non-existent.


Can two lines exist that are not intersecting or parallel explain your answer?

In 2D, NO! In 3D, Yes.


How many electrons in 2d xy?

The 2d sub energy level does not exist. The first shell to contain a d sub-shell is the third shell: the 3d sub-shell contains a maximum of 10 electrons, with two electrons in each of five different d orbitals.


Which of these orbital designations are invalid a. 4s b. 2d c. 3f d. 3p?

The s orbital is present in all valid principal quantum number shells.The p orbital is present in n = 2 and higher.The d orbital is present in n = 3 and higher.The f orbital is present in n = 4 and higher.So the invalid ones are b (there are no 2d orbitals) and c (there are no 3f orbitals). 4s and 3p are perfectly legitimate.


Can a 1p orbital exist?

No, a 1p orbital does not exist. The p orbitals start at the n=2 energy level. Within the p subshell, there are three separate p orbitals (px, py, pz).