No.
Calcium has TWO valence electrons, and Sodium has ONE.
It is lot easier to take off one, than two you see.
However, the second ionization energy of calcium IS however than the second ionization energy of Sodium.
;)
Phosphorus has the highest first ionization energy among phosphorus, calcium, sodium, and aluminum. This is because phosphorus has a higher effective nuclear charge compared to the other elements, making it more difficult to remove an electron from its outer shell.
Sodium (Na) has the lowest first ionization energy in period 3.
The first ionization energy of potassium is 419 kJ/mol, while the first ionization energy of sodium is 496 kJ/mol. This means that it requires less energy to remove an electron from a potassium atom compared to a sodium atom.
Potassium has the smallest first ionization energy among those elements listed. This is because potassium has the largest atomic size and the weakest attraction between its nucleus and outermost electron, making it easier to remove that electron.
Na(g) --> Na+(g) + e- First ionisation energy is always: X(g) --> X+(g) + e- with X being an element
Phosphorus has the highest first ionization energy among phosphorus, calcium, sodium, and aluminum. This is because phosphorus has a higher effective nuclear charge compared to the other elements, making it more difficult to remove an electron from its outer shell.
Sodium's first ionization energy is 495 kJ / mol.
Sodium (Na) has the lowest first ionization energy in period 3.
The first ionization energy of potassium is 419 kJ/mol, while the first ionization energy of sodium is 496 kJ/mol. This means that it requires less energy to remove an electron from a potassium atom compared to a sodium atom.
Potassium has the smallest first ionization energy among those elements listed. This is because potassium has the largest atomic size and the weakest attraction between its nucleus and outermost electron, making it easier to remove that electron.
Beryllium will have the highest. Down a group ionization energy decreases.
Na(g) --> Na+(g) + e- First ionisation energy is always: X(g) --> X+(g) + e- with X being an element
The amount of energy required to remove one mole of electrons from one mole of sodium atoms is known as the ionization energy. In the case of sodium, the first ionization energy is approximately 495.8 kJ/mol. This energy is needed to remove one electron from a sodium atom to form a sodium cation.
No, potassium has a larger first ionization energy than sodium. Potassium has an extra electron in its valence shell compared to sodium, making it more difficult to remove an electron from a potassium atom compared to a sodium atom.
Aluminum has a higher first ionization energy than sodium. This is because aluminum is located further to the right in the periodic table, where elements generally have higher ionization energies due to increased nuclear charge and the effective nuclear attraction on electrons. Sodium, being an alkali metal, has a lower ionization energy as it has a single electron in its outer shell that is more easily removed.
Element P (phosphorus) has a lower first ionization energy than element S (sulfur).
sodium because it's the first group and first group are the most