No, this is a neutralization reaction
2NaOH + H2SO4 --> Na2SO4 + 2H2O
An ionic salt (dissolves in solution ) and water produced.
sulphuric acid
H2SO4 + 2 NaOH --> Na2SO4 + 2 H2O. Sulfuric Acid + Sodium Hydroxide --> Sodium Sulfate + Water.
The reactions of sodium hydroxide and calcium hydroxide with sulfuric acid will produce sodium sulfate and calcium sulfate respectively (water will be another product in both reactions. Sodium sulfate is soluble in water and so will remain in solution. Calcium sulfate, however, is insoluble and will precipitate as a solid.
They are not comparable. Sulfuric acid is corrosive to some other material then Sodium hydroxide and vice verse.
Na2SO4 and H2O
sulphuric acid
H2SO4 + 2 NaOH --> Na2SO4 + 2 H2O. Sulfuric Acid + Sodium Hydroxide --> Sodium Sulfate + Water.
yes but sodium hydroxide will be neutralized by one or both acids
The reactions of sodium hydroxide and calcium hydroxide with sulfuric acid will produce sodium sulfate and calcium sulfate respectively (water will be another product in both reactions. Sodium sulfate is soluble in water and so will remain in solution. Calcium sulfate, however, is insoluble and will precipitate as a solid.
Hydrochloric acid Sulfuric acid Phosphoric acid Sodium hydroxide Calcium hydroxide Potassium hydroxide
They are not comparable. Sulfuric acid is corrosive to some other material then Sodium hydroxide and vice verse.
acid + base = salt + water
Na2SO4 and H2O
Sulfuric acid plus sodium hydroxide gives sodium sulfate plus water.
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
Perhaps the acid H2SO4 ( sulfuric acid ) and the base NaOH ( sodium hydroxide )
Yes, especially - Hydrochloric acid, Nitric acid, Sulfuric acid, Sodium hydroxide and Sodium (bi)carbonate