1 kJ is approximately 0.239 kcal9560 kJ * (0.239 kcal/kJ) = 2284.84 kcal
G=18 kJ/mol
n-butane: -140.7 kJ/mol (liq.) & -124.7 kJ/mol (gas)isobutane: -158.4 kJ/mol (liq.) & -134.5 kJ/mol (gas)
To calculate the value of ΔG at 500 K, you can use the equation ΔG = ΔH - TΔS. Given ΔH = 27 kJ/mol, ΔS = 0.09 kJ/(mol K), and T = 500 K, plug in the values to find ΔG. ΔG = 27 kJ/mol - (500 K)(0.09 kJ/(mol K)) = 27 kJ/mol - 45 kJ/mol = -18 kJ/mol. Therefore, the value of ΔG at 500 K is -18 kJ/mol.
The equation relating G, H, and S is G = H - TS, where T is the temperature in Kelvin. Plugging in the values given, G = 27 kJ/mol - 100 K * 0.09 kJ/(molK) = 27 kJ/mol - 9 kJ/mol = 18 kJ/mol. So, the value for G at 100 K is 18 kJ/mol.
No
50%
Raheja kj somaiya
69
fyjc cutoff list
The K.J. Somaiya Institute is ranked one of the top 15 business schools in India. It offers many courses for post graduates and is affiliated with the University of Mumbai.
The cut-off for FYJC Bifocal Gujarati minority admissions at KJ Somaiya College can vary each year based on factors like the number of applicants and overall performance. For the most accurate and current cut-off information, it's best to check the official college website or contact the admissions office directly.
I JUST WANT TO KNOW WHETHER I WILL GET ADMISSION IN UR COLLEGE AS I HAV SCORE 87% IN HSC EXAMS AND I WANT ADMISSION FOR FYBCom?
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This is my QustionListed below are ionization energies for removing successive electrons from various atoms of the third period. Which of the following lists corresponds to the ionization energies for phosphorus?a. 496 kJ, 4,560 kJ (I.E. for the first two electrons)b. 738 kJ, 1,450 kJ, 7,730 kJ (I.E. for the first three electrons)c. 578 kJ, 1,820 kJ, 2,750 kJ, 11,600 kJ (I.E. for the first four electrons)d. 786 kJ, 1,580 kJ, 3,230 kJ, 4,360 kJ, 16,100 kJ (I.E. for the first five electrons)e. 1,012 kJ, 1,900 kJ, 2,910 kJ, 4,960 kJ, 6,270 kJ (I.E. for the first five electrons)
1000 kj, kj means thousand Jules.