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∆G = ∆H - T∆S∆G = 27 kJ/mole - (500 deg)(0.09 kJ/mol-deg)

∆G = 27 kJ/mole - 45 kJ/mole

∆G = - 18 kJ/mole (Note the minus sign indicating the process is spontaneous)

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Q: What is the value of delta G at 500 K if delta H 27 kJmol and delta S 0.09 kJ(mol K)?
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