The atomic weight of magnesium is 24.31; therefore, the number of moles in 100 gm is 100/24.31 = 4.11, to the justified number of significant digits.
The molar mass of barium (Ba) is approximately 137.3 g/mol. So, the mass of 3 moles of barium would be 3 moles x 137.3 g/mol = 411.9 grams.
C2H4O2 + NaOH = H2O + C2H3O2Na Acetic acid (60 gm) + sodium hydroxide ( 40 gm) = 100 gm water (18 gm) + sodium acetate (82 gm) = 100 gm Ratio reactants to products = 1:1 Molarity = moles / L, 3M = 3 moles / 1 L Acetic acid = 60 gm / total reactant 100gm = 1.8 moles Multiply by 3 = 1.8 moles or 180 grams Sodium Hydroxide = 40 gm / total reactant 100 mg = 1.2 moles or 120 grams. 180 grams acetic acid + 120 grams sodium hydroxide = 300 grams. 300 grams divided by 1 liter = 3M So in order to make 3 M sodium acetate combine solution, add 180 grams acetic acid and 120 grams sodium hydroxide with 1 liter of water.
To calculate the number of moles in 76 grams of NaCl, you need to divide the given mass by the molar mass of NaCl. The molar mass of NaCl is approximately 58.5 g/mol. So, 76 grams of NaCl is equal to 76 g / 58.5 g/mol ≈ 1.30 moles.
To find the number of moles in 16 g of oxygen gas, you need to divide the given mass by the molar mass of oxygen. The molar mass of oxygen (O2) is 32 g/mol. Therefore, 16 g / 32 g/mol = 0.5 moles of oxygen gas.
Molar mass of glucose (C6H12O6) = 180 g/mol. Number of moles of glucose = 16 g / 180 g/mol = 0.089 moles. Volume of solution = 300 ml = 0.3 L. Molarity = number of moles / volume of solution = 0.089 moles / 0.3 L ≈ 0.297 M.
0.25moles
9.991 Moles (water) 8.982 Moles (heavy water)
100.
100
The molar mass of barium (Ba) is approximately 137.3 g/mol. So, the mass of 3 moles of barium would be 3 moles x 137.3 g/mol = 411.9 grams.
1 cup is 250 gm. -So 100 gm is about 2/5 of a cup.
A tablespoon is 15 gm, So 100 gm of butter is 6.6 tbsp
1 tbsp is about 14 gm dry. -So 100 gm flour would be about 7.1 tablespoons.
1 teaspoon is 5 gm. - So 500 gm is 100 teaspoons.
About 717 calories
C2H4O2 + NaOH = H2O + C2H3O2Na Acetic acid (60 gm) + sodium hydroxide ( 40 gm) = 100 gm water (18 gm) + sodium acetate (82 gm) = 100 gm Ratio reactants to products = 1:1 Molarity = moles / L, 3M = 3 moles / 1 L Acetic acid = 60 gm / total reactant 100gm = 1.8 moles Multiply by 3 = 1.8 moles or 180 grams Sodium Hydroxide = 40 gm / total reactant 100 mg = 1.2 moles or 120 grams. 180 grams acetic acid + 120 grams sodium hydroxide = 300 grams. 300 grams divided by 1 liter = 3M So in order to make 3 M sodium acetate combine solution, add 180 grams acetic acid and 120 grams sodium hydroxide with 1 liter of water.
About 81 grams of fat