What is it you are asking? Are you asking what all those compounds have in common? Well, they have chlorine in them. Are you asking to sort them according to their energies of ionization? or solubility? Please be more specific.
2 KClO3 ------ 2KCl + 3O2 so 2 moles of KClO3 produces two mole of KCl. Therefore 0.440 moles of potassium chlorate will produce 0.44 moles of KCl - potassium chloride.
KClO3 --> KCl +O2 - hence the use in explosives chlorate normally made by action of Cl2 on KOH. Another contributor says:- KCl + O2 gives rise to KClO3
You're asking if this is balanced: KClO3 → KCl + O2 Count up each atom of each element and make sure they're equal. On the left side, you have three oxygens. On the right, there are two. So no, this isn't quite balanced. The balanced equation is: KClO3 → KCl + (3/2) O2 Now you have three oxygens on the left side and 3/2 × 2 = 3 oxygens on the right. This is fine, but you might want a whole number mole ratio, in which case you multiply each term by 2. 2 KClO3 → 2 KCl + 3O2
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2
AgNO3(aq) + HCl(aq) --> AgCl(s) + HNO3(aq)
The treatment of AgCl involves filtering and washing the precipitate with water to remove any impurities, then drying the AgCl to obtain a solid residue. The dried AgCl can then be weighed to determine its mass and calculate the amount of chloride in the original sample of KClO3. This information can be used to determine the percent decomposition of KClO3.
It produces HCl instead
2 KClO3 ------ 2KCl + 3O2 so 2 moles of KClO3 produces two mole of KCl. Therefore 0.440 moles of potassium chlorate will produce 0.44 moles of KCl - potassium chloride.
O2 is oxygen molecule; KCl is potassium chloride
KClO3 --> KCl +O2 - hence the use in explosives chlorate normally made by action of Cl2 on KOH. Another contributor says:- KCl + O2 gives rise to KClO3
The balanced equation for the reaction is: 2KF + Cl2 -> 2KCl + F2
This is a decomposition reaction. {Note that the letters "L" in the given question should be lower case "l" instead. Also, the equation as given, assuming an arrow after "KCLO3", is unbalanced.}
You're asking if this is balanced: KClO3 → KCl + O2 Count up each atom of each element and make sure they're equal. On the left side, you have three oxygens. On the right, there are two. So no, this isn't quite balanced. The balanced equation is: KClO3 → KCl + (3/2) O2 Now you have three oxygens on the left side and 3/2 × 2 = 3 oxygens on the right. This is fine, but you might want a whole number mole ratio, in which case you multiply each term by 2. 2 KClO3 → 2 KCl + 3O2
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2
AgNO3(aq) + HCl(aq) --> AgCl(s) + HNO3(aq)
This chemical reaction is known as a decomposition reaction, where a single compound breaks down into two or more simpler substances. In this case, potassium chlorate (KClO3) decomposes into potassium chloride (KCl) and oxygen gas (O2).
KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 After you balance it: 2KMnO4 + 16HCl = 5Cl2 + 8H2O + 2KCl + 2MnCl2