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One can find energy with wavelength by using the equation E hc/, where E represents energy, h is Planck's constant, c is the speed of light, and is the wavelength of the light. This equation shows the relationship between energy and wavelength in electromagnetic radiation.

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5mo ago

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What is the wavelength of the photon that has been released in Part B?

The wavelength of a photon can be calculated using the equation: wavelength = Planck's constant / photon energy. Given the photon energy, you can plug in the values to find the corresponding wavelength.


A photon of wavelength 3000 A is absorbed by a gas and remitted as two photons One of the photons is red 7600 A What is the wavelength of the other photon?

The total energy of a photon with a wavelength of 3000 A is divided into two photons, one red photon with a wavelength of 7600 A, and another photon with a shorter wavelength. To calculate the wavelength of the second photon, you can use the conservation of energy principle, where the sum of the energies of the two new photons is equal to the energy of the original photon. This will give you the wavelength of the other photon.


The minimum energy required to break the oxygen oxygen bond is 495 kJmol The wavelength of sunlight that can cause this bond breakage is 241nm How do you obtain this wavelength?

To find the wavelength, first convert the energy required to break the bond from kJ/mol to J/molecule. Then use this energy value to calculate the frequency of the light required using the formula E=hf, where E is the energy, h is Planck's constant, and f is the frequency. Finally, use the relationship between frequency and wavelength (c = λf) to find the wavelength, where c is the speed of light.


What is the energy in joulesof one photon of microwave radiation with a wavelength of 0.158 m?

The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the radiation. Plugging in the values, we find that the energy of one photon of microwave radiation with a wavelength of 0.158 m is approximately 1.25 x 10^-24 J.


What is the relationship between wavelength of light and the energy of its protons?

The energy in one photon of any electromagnetic radiation is directly proportionalto its frequency, so that would be inversely proportional to its wavelength.Note: There is no energy in the protons of light, since light has no protons.

Related Questions

How do you find the wavelength using binding energy?

To find the wavelength using binding energy, you can use the equation E=hc/λ, where E is the binding energy, h is the Planck constant, c is the speed of light, and λ is the wavelength. Rearrange the equation to solve for the wavelength: λ=hc/E. Plug in the values for h, c, and the binding energy to calculate the wavelength.


How do can you find the energy of a wavelength?

Electromagnetic energy is E=hc/w where w is the wavelength. E= .2E-24 Jm/w.


How are wavelength frequency intensity and energy in an electromagnetic wave?

You will need to have the right formula. The best one to use would be wavelength=frequency/speed of light. to find energy you would need energy=frequency*h. And intensity=power/area.


How are wavelength frequency intensity and energy related in electromagnetic wave?

You will need to have the right formula. The best one to use would be wavelength=frequency/speed of light. to find energy you would need energy=frequency*h. And intensity=power/area.


A photon has an energy of 1.94 1013 J What is the photon's wavelength?

To find the wavelength of the photon, you can use the formula: wavelength = (Planck's constant) / (photon energy). Substituting the values, the wavelength is approximately 1.024 x 10^-7 meters.


Microwave ovens emit microwave energy with a wavelength of 12.0 cm What is the energy of exactly one photon of this microwave radiation?

The energy of one photon of microwave radiation with a 12.0 cm wavelength can be calculated using the formula E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. First, convert the wavelength to meters (0.12 m) and then plug the values into the formula to find the energy of one photon.


What wave would have more enery one with a long wavelength or a short wavelength?

Both a wave with long wavelength and a wave with short wavelength can have a lot of energy, or little energy.Specifically in the case of electromagnetic waves, a short wavelength corresponds to high energy - but this is only the energy PER PHOTON. But note that each of such waves usually consists of a lot of photons.


What does the wavelength of EM wave tell you about its energy?

It tells you that the longer the wavelength the lower the energy. From the wavelength, one can also calculate the actual energy by using E = cxh/lambda where c is speed of light, h is Plank's constant and lambda is the wavelength.


Which transmits more energy if two waves has same amplitude and same speed but differ in wavelength?

The wave with the shorter wavelength will transmit more energy than the one with the longer wavelength if two waves have the same amplitude and same speed but differ in wavelength. The energy transmitted by the shorter wavelength will normally be four times more than the energy transmitted by the longer wavelength.


How does photon energy change with wavelength?

The energy of a photon is inversely proportional to its wavelength. This means that as the wavelength increases, the energy of the photon decreases. Conversely, as the wavelength decreases, the energy of the photon increases.


What is the wavelength of the photon that has been released in Part B?

The wavelength of a photon can be calculated using the equation: wavelength = Planck's constant / photon energy. Given the photon energy, you can plug in the values to find the corresponding wavelength.


What is the energy of one photon of light with a wavelength of 445nm?

The energy of one photon of light with a wavelength of 445nm is about 2.79 electronvolts. This can be calculated using the equation E = hc/λ, where h is the Planck constant, c is the speed of light, and λ is the wavelength.