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First of all, you have to know what substance you are dealing with. Then you would have to know its density. Using the density you can convert liters to kilograms. Then you get the gram-molecular weight (using the chemical formula of this substance and the Periodic Table of Elements) and with that you can convert kilograms to moles.

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How many moles of naoh are contained in 65.0ml of a 2.20m solution of naoh in H2O?

Moles/Liters=Molarity (M) therefore: Molarity*Liters=moles Since you were given milliliters, you must first convert your volume to liters for the equation to be accurate. 2.2M*.065L=moles=.143 moles NaOH


How do you convert 3.58 x 10E22 atoms of Helium to liters?

To convert atoms to liters, you need to use Avogadro's number to find the number of particles in a mole. Then you can use the ideal gas law to convert moles to liters. First, convert the atoms to moles, then use the ideal gas law to find the volume in liters.


How do you convert 200mL to moles?

To convert 200mL to moles, you need to know the substance's molar mass. Once you have the molar mass, you can use the formula moles = volume (in liters) / molar volume to determine the number of moles. Remember to convert milliliters to liters by dividing by 1000.


How do you get from liters of gas to moles do you multiply by 22.4 or divide?

You divide the liters of gas by 22.4 to convert to moles. This is because one mole of gas at standard temperature and pressure (STP) occupies 22.4 liters.


How many moles of HCl are present in 40ml of a 0.035M solution?

Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============


How many moles of sodium chhloride are present in 22.0 ml of 0.500 m solution?

Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------


How many moles of KCL are present in 50.0ml of a 0.552 M solution?

To determine the number of moles of KCl present in a solution, you need to use the formula: moles = molarity x volume (in liters). First, convert the volume from milliliters to liters by dividing by 1000 (50.0 mL = 0.050 L). Then, calculate the moles of KCl by multiplying the molarity (0.552 M) by the volume in liters (0.05 L). This gives you approximately 0.0286 moles of KCl in the solution.


What is the molarity of a solution in which 0.732 moles of HCl are dissolved in 0.975 liters of solution?

Molarity means moles per litre. Whatever you do to the litres to convert them to 1 litre, you have to also do to the moles. 0.732/975*1000 is 0.75077 molar.


What is the molarity of a solution of 73 g of HCL in 2 liters of water?

Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======


How many moles of solute are in 50 mL of a 12 M HCl solution?

To find the number of moles of solute in the solution, first, calculate the amount of HCl in grams using the formula: moles = molarity x volume (in liters). Then, convert the grams of HCl to moles by dividing by the molar mass of HCl (36.46 g/mol).


How do you find molarity with mL?

To find molarity (M) with mL, you need to know the volume in milliliters (mL) of the solution and the amount of solute in moles (mol). Molarity is calculated by dividing the moles of solute by the volume of solution in liters (L). You can convert mL to L by dividing by 1000. The formula for molarity is M = moles of solute / liters of solution.


How many moles of potassium hydroxide are required to prepare 300 mL of 0.250 M solution?

To calculate the moles of potassium hydroxide needed, use the formula: moles = molarity * volume (in liters). First, convert 300 mL to liters (0.3 L). Then, moles = 0.250 mol/L * 0.3 L = 0.075 moles of potassium hydroxide needed to prepare the solution.