You can tell the difference between 1s subshell and 3s subshell using quantum numbers and electron configuration.
Transfer of an electron from a higher energy orbit (2s) to a lower energy orbit (1s) is not possible because it would violate the energy conservation principle. Electrons naturally occupy the lowest available energy levels in an atom, following the Aufbau principle. This means electrons will only move to higher energy levels if they absorb energy, not by transferring between lower and higher energy levels.
The 2s subshell has a higher energy level than the 1s subshell due to the presence of more nodes in the 2s orbital, which increases its energy. Additionally, the 2s orbital has a larger principal quantum number (n) than the 1s orbital, leading to greater distance from the nucleus and therefore higher energy.
It is due to the increased in the effective nuclear charge in argon. Helium has 2 protons in its nucleus. On the other hand, argon has 18 protons in its nucleus.Therefore, it has greater attractive power. Due to this, all the electrons are pulled closer to nucleus.
the 1s orbital is closer to the nucleus and has a lower energy level compared to the 2s orbital. Additionally, the 2s orbital has a slightly higher energy, larger size, and can hold more electrons than the 1s orbital.
An element cannot have 4 electrons in the 2 s level. The s subshell can hold only TWO electrons. Carbon has 4 electrons in the 2p level, however, if that's what you meant.
You can distinguish between the 1s and 3s subshells based on their energy levels and the distance from the nucleus. The 1s subshell is lower in energy and closer to the nucleus, while the 3s subshell is higher in energy and located further away. Additionally, the 3s subshell has a larger radius and can accommodate more energy levels, leading to different electron distributions and shapes.
The K shell is the first shell in an atom and has only one subshell, which is the 1s subshell. This subshell can hold up to 2 electrons.
Transfer of an electron from a higher energy orbit (2s) to a lower energy orbit (1s) is not possible because it would violate the energy conservation principle. Electrons naturally occupy the lowest available energy levels in an atom, following the Aufbau principle. This means electrons will only move to higher energy levels if they absorb energy, not by transferring between lower and higher energy levels.
The electron configuration of phosphorus (atomic number 15) is 1s² 2s² 2p⁶ 3s² 3p³. This indicates that phosphorus has two electrons in the 1s subshell, two in the 2s subshell, six in the 2p subshell, two in the 3s subshell, and three in the 3p subshell. The configuration reflects its position in the periodic table and its chemical properties.
The 2s subshell has a higher energy level than the 1s subshell due to the presence of more nodes in the 2s orbital, which increases its energy. Additionally, the 2s orbital has a larger principal quantum number (n) than the 1s orbital, leading to greater distance from the nucleus and therefore higher energy.
The absolute difference is 1.
The subshell with the lowest effective nuclear charge is typically the 1s subshell. This is because electrons in the 1s subshell are closest to the nucleus and experience a significant amount of shielding from other electrons, which can result in a lower effective nuclear charge for outer subshells. However, when considering only the 1s electrons, they experience the full nuclear charge but are also influenced by electron-electron repulsions, making the effective nuclear charge feel lower for electrons in higher subshells.
The element with four 2p electrons is carbon. In its electron configuration, carbon has a total of six electrons, with two occupying the 1s orbital and four in the 2s and 2p orbitals. Specifically, the configuration is 1s² 2s² 2p², indicating that there are two electrons in the 2s subshell and two in the 2p subshell.
No, the electron configuration 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 4d¹04p⁵ is not valid because it incorrectly suggests that the 4d subshell is filled before the 4p subshell. In the correct order of filling, the 4p subshell would be filled after the 4s and 3d subshells, so the proper configuration for an element with atomic number 35 (bromine) is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁵.
It is due to the increased in the effective nuclear charge in argon. Helium has 2 protons in its nucleus. On the other hand, argon has 18 protons in its nucleus.Therefore, it has greater attractive power. Due to this, all the electrons are pulled closer to nucleus.
In the ground state of atomic silicon, which has an atomic number of 14, there are a total of 14 electrons. The electron configuration is 1s² 2s² 2p⁶ 3s² 3p². Therefore, there are 2 electrons in the 3p subshell.
/1s going upward the others going strait ways.=D