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You cannot balance these two compounds (barium chloride and sodium sulfate, respectively) because they are not in a chemical reaction. However, if you put them in an equation (also known as a reaction), it can be balanced as follows:

BaCl2 => Ba++ + 2Cl2+

Na2SO4 => 2Na+ + SO4-- (SO4 is a polyatomic ion known as sulfate)

Both equations represent what will happen to either of these chemical compounds when they dissolve in water. Both of these ionic compounds are water soluble, and will "break up" into ions in water.

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14y ago

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What is the balanced chemical equation for when barium chloride reacts with sodium sulfate?

This equation is BaCl2 (aq) + Na2SO4 (aq) -> 2 NaCl (aq) + BaSO4 (s).


What is the reaction for Na2SO4 BaCl2?

Test for the anions,according to your word,i think you got the salts,so, use these reagents HCL,BACL2,Adding bacl2 and Hcl to Naso4-white ppt observed in soluble,but barium chloride will give no ppt...so probem solved


Formula for sodium sulfate and barium chloride?

The chemical formula of sodium sulfate is Na2SO4. The chemical formula of barium chloride is BaCl2. BaCl2 + Na2SO4-----------BaSO4 + 2 NaCl BaSO4 is a white, practically insoluble in water precipitate; this property is important in gravimetric analysis.


What is the balanced equation of barium chloride and sodium sulfate include phases?

BaCl2(aq) + Na2SO4 (aq) ------> BaSO4(s) + 2NaCl(aq)


How many grams of solid barium sulfate form when 22.6 mL of 0.160 M barium chloride reacts with 54.6 mL of 0.055 M sodium sulfate?

Balanced equation first. BaCl2 + Na2SO4 -> 2NaCl + BaSO4 22.6 ml BaCl2 = 0.0226 liters 54.6 ml Na2SO4 = 0.0546 liters 0.160 M BaCl2 = moles BaCl2/0.0226 liters = 0.00362 moles BaCl2 0.055 M Na2SO4 = moles Na2SO4/0.0546 liters = 0.0030 moles Na2SO4 The ratio of BaCl2 to Na2SO4 is one to one, so either mole count wull drive this reaction. Use 0.0003 moles Na2SO4 0.0030 moles Na2SO4 (1 mole BaSO4/1 mole Na2SO4)(233.37 grams/1 mole BaSO4) = 0.700 grams of BaCO4 produced


If 57.0 mL of BaCl2 solution is needed to precipitate all the sulfate ion in a 742 mg sample of Na2SO4 what is the molarity of the solution?

To find the molarity of the BaCl2 solution, first calculate the moles of Na2SO4 in the sample using its molar mass. Then, use the balanced chemical equation of the precipitation reaction to determine the moles of BaCl2 needed to react with the moles of Na2SO4. Finally, divide the moles of BaCl2 by the volume of the solution in liters (57.0 mL = 0.057 L) to find the molarity.


An aqueous solution BaCl2 is added to NaSO4 what reaction occurs?

When BaCl2 (barium chloride) is added to Na2SO4 (sodium sulfate), a precipitation reaction occurs, resulting in the formation of a white precipitate of barium sulfate (BaSO4). This is represented by the chemical equation: BaCl2 + Na2SO4 → BaSO4 + 2NaCl.


What kind of reaction is bacl2 na2s04---baso4 2nacl?

The reaction between BaCl2 and Na2SO4 is a double displacement reaction, also known as a precipitation reaction. In this reaction, BaSO4 and 2NaCl are formed as products when BaCl2 and Na2SO4 react. This reaction involves the exchange of ions between the reactants to form new compounds.


What volume of 0.131 M BaCl2 is required to react completely with 42.0 ml of .453 MNa2SO4. This is the net ionic equation for the reaction. Ba2 plus plus SO42---- BaSO4. Correct answer equals 145 ML?

first of all, you need to recognize that one mole of Na2SO4 is reacting with one mole of BaCL2. so find the moles of the NaSO4, then you automatically have the moles of the BaCL2. if you get the moles of the BaCL2, its easy to calculate the volume of it because you already have the MOLARITY. good luck


Is BaCl2 plus Na2SO4 a redox reaction?

Assuming that the intended reaction is BaCl2 (aq) + Na2SO4 (aq) => 2 NaCl (aq) + BaSO4 (s), this is not a redox reaction. Instead it is an ion interchange reaction, driven by the fact that BaSO4 is much less soluble in water than any of the other ions pairs barium chloride, sodium chloride, and sodium sulfate.


Can you Balance bacl2 plus k2so4 equals baso4 plus kcl?

The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is: BaCl2 + K2SO4 -> BaSO4 + 2KCl


What is the equivalent weight of na2so4?

bacl2