To calculate the enrichment factor of the Zn in soil, one must use the Proton Eclat emulator. On the emulator, select the soil type and then determine the nucleus of the enrichment on the soil.
To find the number of moles in 3.80 g of Zn, you first need to calculate the molar mass of Zn, which is 65.38 g/mol. Then, divide the mass given (3.80 g) by the molar mass to get the number of moles, which is approximately 0.058 moles of Zn.
Zn + 2AgNO3 --> Zn(NO3)2 + 2Ag Keq = [Zn(NO3)2][Ag]^2/[Zn][AgNO3]^2 You need concentrations to calculate the Keq Answer from: http://answers.yahoo.com/question/index?qid=20090210150755AAmWI7s
Using the molar mass of zinc (65.38 g/mol), you can calculate the number of moles in 3.65 g of Zn by dividing the given mass by the molar mass. So, 3.65 g of Zn is equivalent to approximately 0.056 moles of Zn.
First, calculate the moles of Zn using its molar mass. Then, use the mole ratio from the balanced chemical equation between Zn and HCl to find the moles of HCl needed. Finally, use the molarity of HCl to calculate the volume in milliliters using the formula: Volume (mL) = moles / molarity.
There is 1 zinc (Zn) atom in Zn(ClO3)2.
To find the number of moles in 3.80 g of Zn, you first need to calculate the molar mass of Zn, which is 65.38 g/mol. Then, divide the mass given (3.80 g) by the molar mass to get the number of moles, which is approximately 0.058 moles of Zn.
Zn + 2AgNO3 --> Zn(NO3)2 + 2Ag Keq = [Zn(NO3)2][Ag]^2/[Zn][AgNO3]^2 You need concentrations to calculate the Keq Answer from: http://answers.yahoo.com/question/index?qid=20090210150755AAmWI7s
Zn(OH)n (s) + -OH(aq) + -> Zn(+n)(aq) + -OH (aq), hope that helps
Using the molar mass of zinc (65.38 g/mol), you can calculate the number of moles in 3.65 g of Zn by dividing the given mass by the molar mass. So, 3.65 g of Zn is equivalent to approximately 0.056 moles of Zn.
First, calculate the moles of Zn using its molar mass. Then, use the mole ratio from the balanced chemical equation between Zn and HCl to find the moles of HCl needed. Finally, use the molarity of HCl to calculate the volume in milliliters using the formula: Volume (mL) = moles / molarity.
The answer is: Zn www.webelements.com Hope this helps. The answer is: Zn www.webelements.com Hope this helps.
Zn:*Zn *for more info: http://www.chemicalaid.com/element.php?symbol=Zn
Zn + CuSO4 --> ZnSO4 + Cu 1.75g CuSO4 * (1moleCuSO4/159.62gCuSO4) * (1moleZn/1moleCuSO4) * (65.38gZn/1moleZn) = .7168g Zn 2.00g Zn - .7168g Zn = 1.2832g Zn in Excess
There is 1 zinc (Zn) atom in Zn(ClO3)2.
To determine the amount of ZnCl2 formed, we first need to find the limiting reactant. Zn is the limiting reactant in this case. The balanced chemical equation is: Zn + 2HCl -> ZnCl2 + H2. Using the given mass of Zn, calculate the moles of Zn, then use the mole ratio from the balanced equation to find the moles of ZnCl2 formed. Finally, convert the moles of ZnCl2 to grams.
The abbreviation Zn stands for the element zinc.
Zinc (Zn) is a metal