- measuring the mass of this compound and the volume (or mass) of the solution
- by chemical analysis (and determination of the concentration of this compound)
If you know the molarity, multiply moles by molecular weight and adjust per the volume you have.
If you don't know the molarity, a simple means is to just evaporate the solvent and weigh the remaining compound
It depends highly on the compound to be dissolved and the solvent. Molarity is measured my moles per litre, and if you don't know the molar mass of the compound, you can't work out the molarity.
The boiling point will be approx. 100,81 0C at 760 mm col. Hg.
67 g/mol
C7H5N3O6 Molarity = moles of solute/Liters of solution (250 ml = 0.25 Liters ) 0.100 M C7H5N3O6 = X moles/0.25 L = 0.025 moles -------------------------now, 0.025 moles C7H5N3O6 (227.14 grams/1 mole C7H5N3O6) = 5.68 grams TNT ====================a good firecracker!
Take twice its molar mass in grams and then dissolve in water up to 1.000 Litre
Only a compound has a molar mass not a solution.
5 mg of an element or compound in 1 L of solution
Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution
Multiply the mass of the compound by the conversion factor based on the percent composition of the element in the compound
Molarity = moles of solute/Liters of solution 10 grams of compound ( 1mol/100g ) = 0.1 mole Molarity = 0.1 mol/1 Liter = 0.1
Put 100 grams in a beaker and and around 500 mls of water until it dissolves, then top up the beaker to a liter. That is your 10% solution. The percentage solution is a ratio of the weight of the compound to the weight of the final solution.
It depends highly on the compound to be dissolved and the solvent. Molarity is measured my moles per litre, and if you don't know the molar mass of the compound, you can't work out the molarity.
Is the makeup of the solution expressed as "percent by mass"? If so, to calculate molarity (or normality), you have to also know the density of the solution Step 1. Lets say the solution is 14%, and the density is 1.09 g/mL. We can write the following: (14 grams solute/100 grams solution) (1.09 grams solution/ mL solution) Step 2. Multiplying and cancelling from step 1 gives you 15.26 grams solute / 100 mL solution. Multiplying top and bottom by 10 gives you 152.6 grams solute per liter. Step 3. Molarity is number of moles per liter. Divide the 152.6 grams of the solute by the forumua weight (or molecular weight) of the solute, and you have the number of moles of solute. This number is therefore the molarity of the solution. If the solution is "percent by volume", the number you have is number of grams per 100 mL. Multiply by 10, and you have grams per liter. Then divide by the formula weight, and you have the molarity.
Since it is a solution it is not a compound but a mixture.
Solute is a compound dissolved in a solution.
The boiling point will be approx. 100,81 0C at 760 mm col. Hg.
67 g/mol