Need to know how much of the solution you have.
The weight of 10 percent acetic acid solution would depend on the total volume of the solution. For example, if you have 100 grams of a 10 percent acetic acid solution, it would contain 10 grams of acetic acid.
You can determine the number of grams of an active ingredient in a solution by multiplying the percent strength of the solution by the total weight or volume of the solution. This will give you the weight of the active ingredient present in the solution.
The percent by weight of NaCl in a saturated solution at 50 degrees Celsius is approximately 26.3%. This means that in every 100 grams of the solution, 26.3 grams is NaCl.
To convert the solution from m percent salty to 2m percent salty, you need to add m/2 grams of salt. This will ensure that the ratio of salt to water in the solution is doubled, resulting in a 2m percent salty solution.
To determine the molality of a solution using the mass percent of the solute, you need to first convert the mass percent to grams of solute per 100 grams of solution. Then, calculate the moles of solute using its molar mass. Finally, divide the moles of solute by the mass of the solvent in kilograms to find the molality of the solution.
40.8 grams
The percent concentration is 13,75 %.
A 10 percent solution of dextrose means that there are 10 grams of dextrose per 100 milliliters of solution. Therefore, in 1000 milliliters (which is 10 times 100 ml), there would be 10 grams x 10 = 100 grams of dextrose in a 1000 ml solution.
The weight of 10 percent acetic acid solution would depend on the total volume of the solution. For example, if you have 100 grams of a 10 percent acetic acid solution, it would contain 10 grams of acetic acid.
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
The answer is 8 g NaCl.
32.4
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
A 25 percent glucose solution means that there are 25 grams of glucose in every 100 milliliters of the solution. Therefore, in 25 milliliters of a 25 percent glucose solution, there would be 6.25 grams of glucose. This concentration is commonly used in medical and laboratory settings for various applications.
200 grams X 0.10 = 20 grams
4314.9 grams
A 5 percent dextrose solution contains 5 grams of dextrose (glucose) per 100 milliliters of solution. Therefore, in one liter (1000 milliliters) of a 5 percent dextrose solution, there would be 50 grams of glucose.