Just like pH is the negative log of [H+], pOH is the negative log of the [OH-].
pH and pOH are a measure of the concentration of the hydronium ions and hydroxyl ions respectively in the solution. pH = -log[H+] pOH = -log[OH-] and they are related: pH + pOH = 14
Ist step, calculate pOH value by using formula pH + pOH = 14 2nd step, pOH = -log[OH], [OH] = - Antilog of pOH
pOH is the negative logarithm of the hydroxide ion concentration in a solution. It is related to pH through the equation: pOH + pH = 14 in an aqueous solution at 25 degrees Celsius. To calculate pOH, you can take the negative logarithm of the hydroxide ion concentration in moles per liter.
pH + pOH = 14 If the pH is 3.4, the pOH is 10.6
The pOH is the negative log of the OH- concentration. Thus, pOH = -log 2.0x10^-2pOH = 1.699 = 1.7
To find the pOH of a solution, you can use the formula pOH = -log[OH⁻]. Given that [OH⁻] = 1.41 × 10⁻¹³, calculate the pOH: pOH = -log(1.41 × 10⁻¹³) ≈ 12.85. Therefore, the pOH of the solution is approximately 12.85.
pH and pOH are a measure of the concentration of the hydronium ions and hydroxyl ions respectively in the solution. pH = -log[H+] pOH = -log[OH-] and they are related: pH + pOH = 14
To find the pOH of a solution, you can use the formula pOH = -log[OH⁻]. Given that the concentration of hydroxide ions [OH⁻] is 2.010 × 10⁻² M, you would calculate pOH as follows: pOH = -log(2.010 × 10⁻²) ≈ 1.69. Thus, the pOH of the solution is approximately 1.69.
Ist step, calculate pOH value by using formula pH + pOH = 14 2nd step, pOH = -log[OH], [OH] = - Antilog of pOH
pOH is the negative logarithm of the hydroxide ion concentration in a solution. It is related to pH through the equation: pOH + pH = 14 in an aqueous solution at 25 degrees Celsius. To calculate pOH, you can take the negative logarithm of the hydroxide ion concentration in moles per liter.
To calculate the concentration of hydroxide ions (OH-) from a given pH value, you can use the formula: [OH-] = 10^(-pH). For a pH of 1.12, the concentration of hydroxide ions would be [OH-] = 10^(-1.12) = 0.079 moles per liter.
pH + pOH = 14 If the pH is 3.4, the pOH is 10.6
The pOH is the negative log of the OH- concentration. Thus, pOH = -log 2.0x10^-2pOH = 1.699 = 1.7
The pH of a solution is a measure of its acidity or basicity. To calculate the pH from the hydroxide concentration, you would first need to convert the concentration to a pOH value using the equation pOH = -log[OH-]. Then, you can calculate the pH using the relationship pH + pOH = 14.
To find the concentration of hydroxide ions (OH⁻) in a solution with a pH of 11.70, first, calculate the pOH using the formula pOH = 14 - pH. This gives pOH = 14 - 11.70 = 2.30. Then, use the relationship between pOH and hydroxide concentration: OH⁻ = 10^(-pOH). Therefore, the concentration of OH⁻ is approximately 0.00512 M.
To calculate the pH of a weak base solution, you first need to determine the concentration of the base and the equilibrium constant (Kb) for the base's reaction with water. Then, use the equation pH 14 - pOH, where pOH is calculated using the concentration of the base and Kb. Finally, calculate the pH using the pOH value.
First u need to know the pH of sulfuric acid: ph= -log[h+] =-log[0.4] 0.3979 now u can find out the POH of sulfuric acid ph+poh=14 poh=14-0.3979 poh=13.6