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At STP 1 mole of every gas has the volume of 22.4 dm3. (1 dm3 = 1 L)
According to previous law,
1 mol - 22.4 dm3
x - 5.68 dm3
--------------------------
x = 0.2536 mol
1 mol of NO weights 30 g (Ar for N is 14, and Ar for O is 16. Mr(NO) = Ar(N) + Ar(O)), so
1 mol - 30 g
0.2536 mol - x
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x = 7.6080 g
So the mass of 5.68 L of NO at STP is 7.6080 grams.
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What is the mass of ethane gas inside a 5.00 L vessel at STP?
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