At STP 1 mole of every gas has the volume of 22.4 dm3. (1 dm3 = 1 L)
According to previous law,
1 mol - 22.4 dm3
x - 5.68 dm3
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x = 0.2536 mol
1 mol of NO weights 30 g (Ar for N is 14, and Ar for O is 16. Mr(NO) = Ar(N) + Ar(O)), so
1 mol - 30 g
0.2536 mol - x
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x = 7.6080 g
So the mass of 5.68 L of NO at STP is 7.6080 grams.
The mass of 43,7 L of helium at STP is 7.8 g.
At STP, the molar volume of any ideal gas is 22.4 L/mol. To find the density of CCl4 vapor at STP, we need to calculate its molar mass. CCl4 has a molar mass of 153.8 g/mol, so the density of CCl4 vapor at STP would be 153.8 g/mol divided by 22.4 L/mol, which equals approximately 6.86 g/L.
To calculate the mass of FeO2 produced, we first need to find the number of moles of O2 using the ideal gas law: PV = nRT. At STP, 1 mole of gas occupies 22.4 L, so 50.0 L of O2 is 50.0/22.4 = 2.23 moles. The balanced equation for the reaction will tell you the stoichiometry needed to calculate the mass of FeO2 produced.
The molar volume of a gas at STP (Standard Temperature and Pressure) is 22.4 L. Ethane gas has a molar mass of 30.07 g/mol. Therefore, the mass of ethane gas in a 5.00 L vessel at STP can be calculated as (5.00 L / 22.4 L) * 30.07 g/mol.
To find the mass of 99.01 moles of NO2 at STP (Standard Temperature and Pressure), you can use the ideal gas law. At STP, one mole of any gas occupies 22.4 L, so 99.01 moles of NO2 would occupy 99.01 x 22.4 = 2219.02 L. Using the molar mass of NO2 (46.01 g/mol), you can calculate the mass by multiplying the number of moles by the molar mass. So, 99.01 moles x 46.01 g/mol = 4546.46 grams.
The mass of 43,7 L of helium at STP is 7.8 g.
At STP, the molar volume of any ideal gas is 22.4 L/mol. To find the density of CCl4 vapor at STP, we need to calculate its molar mass. CCl4 has a molar mass of 153.8 g/mol, so the density of CCl4 vapor at STP would be 153.8 g/mol divided by 22.4 L/mol, which equals approximately 6.86 g/L.
To calculate the mass of FeO2 produced, we first need to find the number of moles of O2 using the ideal gas law: PV = nRT. At STP, 1 mole of gas occupies 22.4 L, so 50.0 L of O2 is 50.0/22.4 = 2.23 moles. The balanced equation for the reaction will tell you the stoichiometry needed to calculate the mass of FeO2 produced.
The molar volume of a gas at STP (Standard Temperature and Pressure) is 22.4 L. Ethane gas has a molar mass of 30.07 g/mol. Therefore, the mass of ethane gas in a 5.00 L vessel at STP can be calculated as (5.00 L / 22.4 L) * 30.07 g/mol.
At Standard Temperature and Pressure (STP), which is defined as 0 degrees Celsius (273.15 Kelvin) and 1 atmosphere pressure, the molar volume of an ideal gas is approximately 22.4 liters/mol. The molar mass of nitrogen gas (N₂) is approximately 28.02 grams/mol. To calculate the density (D) of nitrogen gas at STP, you can use the ideal gas law: � = Molar mass Molar volume at STP D= Molar volume at STP Molar mass � = 28.02 g/mol 22.4 L/mol D= 22.4L/mol 28.02g/mol � ≈ 1.25 g/L D≈1.25g/L Therefore, the density of nitrogen gas at STP is approximately 1.25 grams per liter.
The molar volume of any ideal gas at standard temperature and pressure (STP) is 22.4 L/mol. Converting 39.6 dm3 to liters gives 39.6 L. To find the mass of argon gas, we calculate the number of moles using the ideal gas equation (PV = nRT) and then multiply by the molar mass of argon.
1 standard volume of 1 mole of any gas @ STP is 22.4 LSo the # of moles in a 1 L sample will be:1 L*(1 mol/22.4 L) = 0.04464 molSince you already know the mass of the gas @ STP, the molar mass will be mass/#moles1.92 g/ 0.04464 mol = 43.01 g/mol
The weight of 75.0 L of helium depends on the temperature and pressure at which it is measured. At standard temperature and pressure (STP), which is 0°C and 1 atmosphere, the molar mass of helium is 4.0 grams per mole. Using the ideal gas law, we can calculate the weight by multiplying the molar mass of helium by the number of moles, which is the volume divided by 22.4 L (molar volume at STP). However, if the temperature and pressure are not at STP, additional information is needed to determine the weight.
To find the mass of 99.01 moles of NO2 at STP (Standard Temperature and Pressure), you can use the ideal gas law. At STP, one mole of any gas occupies 22.4 L, so 99.01 moles of NO2 would occupy 99.01 x 22.4 = 2219.02 L. Using the molar mass of NO2 (46.01 g/mol), you can calculate the mass by multiplying the number of moles by the molar mass. So, 99.01 moles x 46.01 g/mol = 4546.46 grams.
1 mole SO2 weights 32+2*16 = 64 gram S + 2*O and it's volume is 22.4 l You can do with that to calculate density (g/L) ?
The molar volume of a gas at STP is 22.4 liters/mol. The molar mass of hydrogen bromide is 80.9 g/mol. Therefore, the density of hydrogen bromide at STP is 80.9 g/mol / 22.4 L/mol = 3.61 g/L.
To find the weight of 2350 L of O2 gas at STP, you would first need to calculate the moles of gas using the ideal gas law. Then, use the molar mass of O2 to convert moles to grams. The molar mass of O2 is 32 g/mol, so you would multiply the moles by 32 g/mol to find the weight in grams.