There is no need for using Avogadro's number ( 1 mole is 6.02*10^23 particles ) to calculate that there is 1.0 mole in 23 g Na, because you only need the Atomic Mass of sodium being 23.0 gram per mole
To determine the number of atoms in 46.0 grams of sodium, you first need to calculate the number of moles of sodium present. With the molar mass of sodium being 22.99 g/mol, you can divide the given mass by the molar mass to find the number of moles. Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to atoms by multiplying the number of moles by Avogadro's number.
To determine the number of sodium ions in 85g of sodium oxide (Na2O), first calculate the molar mass of Na2O. This can be done by adding the atomic masses of sodium (Na) and oxygen (O) in the compound. Then, find the number of moles of Na2O in 85g using the molar mass. Since Na2O contains 2 sodium ions per formula unit, multiply the number of moles by 2 to find the number of sodium ions.
One mole is 6.02*1023 atoms. So to find out how many moles are in 1.43*1024 , it's as simple as dividing the second number by the first. This results in 2.38 moles (rounded to significant figures)
First calculate the moles of sodium moles = 500 g/ 23 = 21.739 ... Remember the Avogadro Number. 6.022 x 10^(23) is the number of atoms in one mole Hence , multiplying 6.022 x 10^(23) X 21.739... = 1.309 x 10^(25) atoms in 0.5 kg of sodium .
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
To determine the number of atoms in 46.0 grams of sodium, you first need to calculate the number of moles of sodium present. With the molar mass of sodium being 22.99 g/mol, you can divide the given mass by the molar mass to find the number of moles. Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to atoms by multiplying the number of moles by Avogadro's number.
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
The answer is 0,12.10ex23 sodium cations.
To calculate the number of sodium ions present in 38.1 grams of sodium chloride, you first need to determine the number of moles of sodium chloride using its molar mass. Then recognizing that each unit of sodium chloride contains one sodium ion, you can say there are one mole of sodium ions present. Finally, you can convert the moles of sodium ions into the number of sodium ions using Avogadro's number (6.022 x 10^23 mol^-1).
1, because Na does not have a number after it.
To calculate the grams of sodium hydroxide present in the solution, first calculate the number of moles using the formula: moles = Molarity (M) x Volume (L). Then, use the molar mass of sodium hydroxide (NaOH) to convert moles to grams. The molar mass of NaOH is 40 g/mol. Thus, in this case, you have 0.3375 moles of NaOH and if you convert this to grams, it would be 13.5 grams.
Calculate the percent by weight of sodium (Na) and chlorine (Cl) in sodium chloride (NaCl) * Calculate the molecular mass (MM):MM = 22.99 + 35.45 = 58.44 * Calculate the total mass of Na present:1 Na is present in the formula, mass = 22.99 * Calculate the percent by weight of Na in NaCl:%Na = (mass Na ÷ MM) x 100 = (22.99 ÷ 58.44) x 100 = 39.34% * Calculate the total mass of Cl present:1 Cl is present in the formula, mass = 35.45 * Calculate the percent by weight of Cl in NaCl:%Cl = (mass Cl ÷ MM) x 100 = (35.45 ÷ 58.44) x 100 = 60.66% The answers above are probably correct if %Na + %Cl = 100, that is,39.34 + 60.66 = 100.
To calculate the number of moles of sodium carbonate in 212g, you need to first determine the molar mass of Na2CO3 (sodium carbonate). The molar mass of Na2CO3 is 105.99 g/mol. Then, you divide the given mass (212g) by the molar mass to find the number of moles (212g / 105.99 g/mol = 1.999 moles).
To find the number of sodium atoms in 0.2310 g of sodium, you need to convert the mass to moles using the molar mass of sodium (22.99 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. This calculation will give you the number of sodium atoms present in 0.2310 g of sodium.
To determine the number of moles of sodium carbonate in 2 grams of hydrated sodium carbonate, we first need to calculate the molar mass of Na2CO3·xH2O. Once we have the molar mass, we can use the formula: Moles = Mass / Molar mass. Given that hydrated sodium carbonate has the molar mass of Na2CO3·xH2O, we can determine the number of moles in 2 grams of the compound.
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To determine the number of sodium ions in 85g of sodium oxide (Na2O), first calculate the molar mass of Na2O. This can be done by adding the atomic masses of sodium (Na) and oxygen (O) in the compound. Then, find the number of moles of Na2O in 85g using the molar mass. Since Na2O contains 2 sodium ions per formula unit, multiply the number of moles by 2 to find the number of sodium ions.