The answer is too complex for this context. You can find it here:
Calculation of the equilibrium pH in a multiple-buffered aqueous solution based on partitioning of proton buffering: a new predictive formula.
Minhtri K. Nguyen, Liyo Kao and Ira Kurtz
Am J Physiol Renal Physiol 296:F1521-F1529, 2009.
First published 1 April 2009;
doi:10.1152/ajprenal.90651.2008
To calculate pKa, you can use the Henderson-Hasselbalch equation: pKa = pH + log([A−]/[HA]), where [A−] is the concentration of the conjugate base and [HA] is the concentration of the acid. Alternatively, you can look up the pKa value in a table or use a chemical database.
HA ==> H+ + A-Ka = [H+][A-][HA] and from pH = 2.31, calculated [H+] = 4.89x10^-3 M Ka = (4.89x10^-3)(4.89x10^-3)/0.012 Ka = 1.99x10^-3 pKa = 2.70
To calculate the isoelectric point using 3 pKa values, find the average of the two pKa values closest to the pH at which the molecule carries no net charge.
To calculate the isoelectric point using three pKa values, find the average of the two pKa values closest to the pH at which the molecule carries no net charge.
To calculate the pKa from a titration curve, identify the point on the curve where the concentration of the acid and its conjugate base are equal. This is the half-equivalence point. The pH at this point is equal to the pKa of the acid.
You can calculate the pKa value by using the Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA]), where [A-] is the concentration of the conjugate base and [HA] is the concentration of the acid. Rearranging the equation, you can solve for pKa by taking the antilog of both sides after isolating pKa.
To calculate pKa, you can use the Henderson-Hasselbalch equation: pKa = pH + log([A−]/[HA]), where [A−] is the concentration of the conjugate base and [HA] is the concentration of the acid. Alternatively, you can look up the pKa value in a table or use a chemical database.
HA ==> H+ + A-Ka = [H+][A-][HA] and from pH = 2.31, calculated [H+] = 4.89x10^-3 M Ka = (4.89x10^-3)(4.89x10^-3)/0.012 Ka = 1.99x10^-3 pKa = 2.70
To calculate the isoelectric point using 3 pKa values, find the average of the two pKa values closest to the pH at which the molecule carries no net charge.
To calculate the isoelectric point using three pKa values, find the average of the two pKa values closest to the pH at which the molecule carries no net charge.
To calculate the pKa from a titration curve, identify the point on the curve where the concentration of the acid and its conjugate base are equal. This is the half-equivalence point. The pH at this point is equal to the pKa of the acid.
To calculate the pH of a buffer solution, you can use the Henderson-Hasselbalch equation, which is pH pKa log(A-/HA), where pKa is the negative logarithm of the acid dissociation constant, A- is the concentration of the conjugate base, and HA is the concentration of the weak acid in the buffer solution.
pKa= pH - log(A/HA) to clarify -log is subtract log E.g A buffer is prepared by adding .15 M of NaOH and .1 of a weak acid, HA. If the pH of the buffer is 8.15, what is the pKa of the acid? pH= 8.15 - log .15/.1 = 7.97
To calculate the pH of a buffer solution, you can use the Henderson-Hasselbalch equation, which is pH pKa log(A-/HA). Here, pKa is the negative logarithm of the acid dissociation constant, A- is the concentration of the conjugate base, and HA is the concentration of the weak acid. By plugging in these values, you can determine the pH of the buffer solution.
To calculate the pH of a buffer solution, you can use the Henderson-Hasselbalch equation, which is pH pKa log(A-/HA). Here, pKa is the negative logarithm of the acid dissociation constant, A- is the concentration of the conjugate base, and HA is the concentration of the weak acid in the buffer solution. By plugging in these values, you can determine the pH of the buffer solution.
pH = pKa + log([A-]/[HA]) pH = pKa+log([conjugate base]/[undissociated acid]) pKa is also a measure of the strength of an acid. A low pKa is a strong acid, a higher pKa is a weak acid.
Yes, if the pH is less than the pKa, the compound will be protonated.