Take twice its molar mass in grams and then dissolve in water up to 1.000 Litre
To convert the solution from m percent salty to 2m percent salty, you need to add m/2 grams of salt. This will ensure that the ratio of salt to water in the solution is doubled, resulting in a 2m percent salty solution.
To make a 2 M solution of a compound, you would first need to determine the molar mass of the compound. Once you have the molar mass, you can calculate the amount of compound needed to make the solution by using the formula: moles = Molarity x Volume (in liters). Finally, dissolve the calculated amount of compound in the appropriate volume of solvent to make a 2 M solution.
To prepare 250ml of a 2M potassium chloride solution, measure out 17.8g of potassium chloride and dissolve it in water to make a total volume of 250ml. Make sure to stir the solution well to ensure the potassium chloride is completely dissolved. Then, adjust the final volume to exactly 250ml by adding more water if needed.
The pH of a 2M HCl solution is around 0. This is because HCl is a strong acid that dissociates completely in water to produce H+ ions, leading to a highly acidic solution.
By the definition of molarity, which is mass of solute in moles divided by solution volume in liters, 250 ml of 0.15 M NaCl* solution requires (250/1000)(0.15) or 0.0375 moles of NaCl. Each liter of 2M NaCl solution contains 2 moles of NaCl. Therefore, an amount of 0.0375 moles of NaCl is contained in (0.0375/2) liters, or about 18.75 ml of the 2M NaCl, and if this volume of the more concentrated solution is diluted to a total volume of 250 ml, a 0.15 M solution will be obtained. _________________ *Note correct capitalization of the formula.
To convert the solution from m percent salty to 2m percent salty, you need to add m/2 grams of salt. This will ensure that the ratio of salt to water in the solution is doubled, resulting in a 2m percent salty solution.
In order to have a 2M solution is means that you have 2 moles for every 1 liter. Because you only want to make 800mL of this solution you only need (0.8*2) moles of or 1.6 moles of the compound in your solution. This 1.6 moles is coming from your 5M solution. So how much 5M do you need to take out to have 1.6 moles. A 5 molar solution has 5 moles for every liter, since you only need 1.6 moles of it that you need(1.6/5) liters of the solution or 0.32 liters (320 mL). Calculations done. So your going to take 320 mL of the 5M solution and put it into an 800mL volumetric flask and add water up to the line, or to be more exact, add exactly 460 mL of water in order to dilute the solution from 5M to 800mL of 2M solution.
no they do not they make a solution
2M NaCl is a equivalent to a solution with 116,88 g NaCl in 1 L water.
A 2M solution of hydrochloric acid would contain 2 moles of hydrochloric acid per liter of solution. To determine the amount of hydrochloric acid in a certain volume of 2M solution, you can use the formula: moles = Molarity x Volume (in liters).
To make a 2 M solution of a compound, you would first need to determine the molar mass of the compound. Once you have the molar mass, you can calculate the amount of compound needed to make the solution by using the formula: moles = Molarity x Volume (in liters). Finally, dissolve the calculated amount of compound in the appropriate volume of solvent to make a 2 M solution.
To prepare 250ml of a 2M potassium chloride solution, measure out 17.8g of potassium chloride and dissolve it in water to make a total volume of 250ml. Make sure to stir the solution well to ensure the potassium chloride is completely dissolved. Then, adjust the final volume to exactly 250ml by adding more water if needed.
A. Almost completely positive.
We're not sure what the question means by "root". It may be what's usuallyreferred to as the "solution" of the equation ... the number that 'm' must be inorder to make the equation a true statement. Here's how to find the 'solution':2m + 7 = 8 + mSubtract 7 from each side:2m = 1 + mSubtract 'm' from each side:m = 1
This compound is not soluble in water.
You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.
To prepare a 25 mL solution of 2M calcium chloride (CaCl₂), you need to calculate the amount of CaCl₂ required. First, use the formula: [ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} ] For a 2M solution in 0.025 L (25 mL), you need 0.05 moles of CaCl₂. The molar mass of CaCl₂ is approximately 110.98 g/mol, so you would weigh out about 5.55 grams of CaCl₂ and dissolve it in enough water to make a final volume of 25 mL.