What is the Process for standardization of 0.5NKOH using Sodium Hydrogen phthalate.
18 grams of KOH add 10 ml of water dilut with methanol to 500 ml. allow to stand for 24 hours. filter into a polyethylene bottle.
Take 5.7g of KOH and dissolve in 1dm of water
Dissolve 30 g KOH in 100 mL methanol.
Molarity = moles of solute/Liters of solution ( 220.0 ml = 0.220 Liters ) 0.500 M KOH = moles KOH/0.220 Liters = 0.110 moles KOH (56.108 grams/1 mole KOH) = 6.17 grams solid KOH needed
You weight 14,5 gramm KOH in a bottle and than fill that bottle with deionized water till it holds 500ml.
28 gram. = 2 * 56 * 250 / 1000
Take 5.7g of KOH and dissolve in 1dm of water
Dissolve 30 g KOH in 100 mL methanol.
Molarity = moles of solute/Liters of solution ( 220.0 ml = 0.220 Liters ) 0.500 M KOH = moles KOH/0.220 Liters = 0.110 moles KOH (56.108 grams/1 mole KOH) = 6.17 grams solid KOH needed
You weight 14,5 gramm KOH in a bottle and than fill that bottle with deionized water till it holds 500ml.
Molarity = moles of solute/liters of solution ( 300 ml = 0.300 liter ) 0.250 molar KOH = moles KOH/0.300 liters = 0.075 moles KOH
28 gram. = 2 * 56 * 250 / 1000
What volume(L) of 3M KOH solution can be perpared by diluting 0.5 L of %M KOH solution?
Molarity = moles of solute/volume of solution 0.500 M KOH = moles KOH/125 ml 62.5 millimoles, or to answer the question precisely, 0.0625 moles KOH
KOH is used to prepare liquid soaps.
Moles KOH = Molarity x Volume = 0.214 moles/liter x 0.0602 liters = 0.0129 moles KOH. Remember, 60.2 mL = 0.062L
because KOH is hygroscopic
1% solution of KOH contains 1g of KOH in 100g of solution. This means that you need to mix 1g of KOH and 99g of water.