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Q: How do you prepare 0.5 molar solution of H2SO4?

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fehling's solution is dark blue at room temperature "Fehling's solution" is prepared by dissolving separately 34'639 grammes of copper sulphate, 173 grammes of Rochelle salt, and 71 grammes of caustic soda in water, mixing and making up to l000 ccs.; 10 ccs. of this solution is completely reduced by o 05 grammes of hexose

Moles of the soild = 1.78/ 208 = .00856 moles of H2O = 0.90/ 18 =.05 therefore number of moles of water for 1 mole of solid = .05/.00856 = approx 6

If you are asking if x=0, y=5 is a solution to 5x-3y=15, then no. 0, -5 would be as if you sub in 0 for x you get 5(0) -3y=15, i.e. -3y=15, i.e. y=-5

.05 L x 342 (this is the molecular weight of sucrose) x 1.75 = 29.925g

0.1

The date 25-05-05 in Roman numerals is XXV.V.V and the date 25-05-2005 is XXV.V.MMV

(.05)X(grams of total solution) = grams of acetic acid (grams of acetic acid)/ (mol. wt. of acetic acid(=60g/mol)) = mol. acetic acid (mol. acetic acid)/ (Liters of total solution) = molarity(M)

05 what you must put in a label for 05 for anyone to find out for you

04:05 or 16:05

In a normal periodic table, the molar mass of a given element, is made up of multiplying the mass of a given isotope of that element, with the abundance of that given isotope in percent. For example, Say for the element X, you know that it has two isotopes, X12 and X13. X12 has a molar mass of 12 g/mol, and you know that of all the X molecules in the world, X12 is found 95% of the time, X13 has a molar mass of 13g/mol, yet its abundence is only 5%. Therefore average molar mass for element X is calculated as such, (12 * .95)+(13*.05) = 12.05 g/mol. hope that helps.

Howard Stern on Demand - 2005 Best of 05 01-05 05 2006 was released on: USA: May 2006

05 is the same as 5

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