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At low concentrations, normality and molarity are about the same. So figure out how many grams are in a mole of KOH: K-39, O-16, H-1, so 39+16+1=56g/mol. 0.05 moles would be 56(.05)=2.8g, so dissolve 2.8 grams of KOH in a liter of water and you're there.
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How many grams of solid KOH is necessary to prepare 220.0 ml of 0.500 M KOH solution?
Molarity = moles of solute/Liters of solution ( 220.0 ml = 0.220 Liters ) 0.500 M KOH = moles KOH/0.220 Liters = 0.110 moles KOH (56.108 grams/1 mole KOH) = 6.17 grams solid KOH needed
How many moles are in 234.1 grams of KOH?
Molar mass of KOH = 39.1+16.0+1.0 = 56.1Amount of KOH = mass of sample / molar mass = 32/56.1 = 0.570mol
How do you prepare 0.002N methanolic KOH?
Molar mass KOH = 56g/mol and 0.002 N KOH = 0.002 moles/L0.002 moles/L x 56 g/mole = 0.112 g/LDissolve 0.113 grams KOH in 1 liter or methanol, or any fraction/multiple thereof. For example, dissolve 0.0113 g KOH in 100 mls or dissolve 0.226 g in 2 liters of methanol.
What mass of h2o is produced when 0.400 moles of koh react completely in the following equation koh plus hcl equals kcl plus h2o?
I assume KOH is limiting. Balanced equation. KOH + HCl -> KCl + H2O 0.400 moles KOH (1 mole H2O/1 mole KOH)(18.016 grams/1 mole H2O) = 7.21 grams water produced =====================
How many moles of KOH are represented by 1.350g of KOH?
1 mole of KOH is 56.1074 grams1.350 g/56.1074 g =0.02406 (2.406 x 10^-2) moles of KOH
How many grams of solid KOH is necessary to prepare 220.0 ml of 0.500 M KOH solution?
Molarity = moles of solute/Liters of solution ( 220.0 ml = 0.220 Liters ) 0.500 M KOH = moles KOH/0.220 Liters = 0.110 moles KOH (56.108 grams/1 mole KOH) = 6.17 grams solid KOH needed
How do you get 6 ltr from a 7 ltr jar and a 4 ltr jar?
Fill 4 ltr jar State of two jars: (4, 0)Pour from 4 ltr to 7 ltr: (0, 4)Refill 4 ltr: (4, 4)Pour from 4 ltr to 7 ltr jar until it is full: (1, 7)Empty 7 ltr: (1, 0)Pour from 4 lts to 7 ltr: (0, 1)Fill 4 ltr: (4, 1)Pour from 4 ltr to 7 ltr jar: (0, 5)Fill 4 ltr: (4, 5)Pour from 4 ltr to 7 ltr jar until it is full: (2, 7)Empty 7 ltr: (2, 0)Pour from 4 lts to 7 ltr: (0, 2)Fill 4 ltr: (4, 2)Pour from 4 ltr to 7 ltr jar: (0, 6)Done.
Is 750ml the same as 1 ltr?
No, there are 1000ml in 1 ltr. Therefore 750ml is 3/4 of a litre.
How much 2 stroke do you mix with 5ltr of prtrol if the mix ratio is 10 to 1?
if 10 to 1 is 1 ltr of oil for every 10 ltr of fuel then math is easy 5 ltr of fuel would get .5 ltr or one half liter of oil.
How many milliliters in half liters?
1/2 liter equals 500 mL (1,000 mL in each liter).
How tall is Koh Yamamoto?
Koh Yamamoto is 6' 1".
How many moles are in 234.1 grams of KOH?
Molar mass of KOH = 39.1+16.0+1.0 = 56.1Amount of KOH = mass of sample / molar mass = 32/56.1 = 0.570mol
How do you prepare 0.002N methanolic KOH?
Molar mass KOH = 56g/mol and 0.002 N KOH = 0.002 moles/L0.002 moles/L x 56 g/mole = 0.112 g/LDissolve 0.113 grams KOH in 1 liter or methanol, or any fraction/multiple thereof. For example, dissolve 0.0113 g KOH in 100 mls or dissolve 0.226 g in 2 liters of methanol.
What is the oxidation for KOH?
K is +1 O is -2 H is +1
How many atoms in 4KOH?
1 fomula unit of KOH has 3 atoms: 1 potassium (K), 1 oxygen (O), and 1 hydrogen (H).
How many liter 1 scfh?
1 scfh = 0.4719474 ltr/min1 scfh = 0.4719474 ltr/minNop!!1 ft^3/h = 28.316847 ltr/h (exactly) = 0.4719474.. ltr/minThis expression is absolutely correct, but the following shall be noted:the "standard state" in "English Unit" usually means 60℉ and 1 atmosphere, while the "normal state" in "Metric Unit" is based on 0℃ 1 atmosphere.1 scfh = 1 std. ft^3/h = [0.4719474 * (460+32)R/(460+60)R] N ltr/h= 26.79209.. N ltr/h = 0.446535 N ltr/minSo the word 'standard state' shall clearly be definedStefano Kim, Korea
What mass of h2o is produced when 0.400 moles of koh react completely in the following equation koh plus hcl equals kcl plus h2o?
I assume KOH is limiting. Balanced equation. KOH + HCl -> KCl + H2O 0.400 moles KOH (1 mole H2O/1 mole KOH)(18.016 grams/1 mole H2O) = 7.21 grams water produced =====================
