Density of etyl acetate
To prepare a 200ml solution with a sodium concentration of 5ppm from a 1000ppm stock solution, you will first dilute the stock solution by a factor of 200. So, take 0.2ml of the 1000ppm solution and dilute it to 40ml with water. This will give you a solution with a concentration of 50ppm. Then, take 0.4ml of this 50ppm solution and dilute it to a final volume of 200ml with water to achieve the desired 5ppm sodium concentration.
The time required to administer 200ml of glucose IV solution would depend on the rate of administration, typically measured in ml per hour. For example, if the rate is set at 100ml per hour, then administering 200ml would take 2 hours.
NaCl has a molar mass of 22,989 769 28 + 35,453 = 58,442 769 28 g Na has an atomic weight of 22,989 769 28 g. % Na = 22,989 769 28 ÷ 58,442 769 28 = 39,337 200 mL of 0,45 % sodium chloride contain 0,9 g NaCl. Mass of Na in 0,9 grams of NaCl = 0,39337 x 0,9 g = 0,354 g
To prepare a 200ml solution of 0.5M H2SO4, you need to add 12.5ml of 8M H2SO4 and then dilute it up to 200ml. Well, this is how to calculate it, I'll go straight to the equation. use the M1V1 = M2V2 equation, M1 = 8.0 M V1 = Volume needed M2 = 0.5 M V2 = 200 ml 8.0 M x V1 = 0.5 M x 200 ml V1 = (0.5 M x 200 ml)/ 8.0 M = 12.5 ml Cheers :)
The amount of salt that can be dissolved in 200ml of water at room temperature depends on the solubility of salt in water. Typically, at room temperature, you can dissolve about 36 grams of salt in 200ml of water.
To prepare 200ml of 80% glycerol solution, you would mix 160ml of glycerol (200ml x 80%) with 40ml of water. Calculations: 200ml x 80% = 160ml glycerol, and 200ml - 160ml = 40ml water needed. Mix the glycerol and water thoroughly to obtain the 80% glycerol solution.
Dissolve 0.4 g of NaOH in 100 ml of water. Try it out. Actually it is not suitable to prepare NaOH solutions in standard flasks.It should be made in beakers & must be standardised..This is done to find the correct normality...
200ml of solution x 20% of alcohol = 40ml of alcohol..
To prepare a 200ml solution with a sodium concentration of 5ppm from a 1000ppm stock solution, you will first dilute the stock solution by a factor of 200. So, take 0.2ml of the 1000ppm solution and dilute it to 40ml with water. This will give you a solution with a concentration of 50ppm. Then, take 0.4ml of this 50ppm solution and dilute it to a final volume of 200ml with water to achieve the desired 5ppm sodium concentration.
10g/200ml=5g/100ml = 5% solution. Now read your Dosage and Calculations book and prepare for the test because it is Monday. Good luck!
a lot
The time required to administer 200ml of glucose IV solution would depend on the rate of administration, typically measured in ml per hour. For example, if the rate is set at 100ml per hour, then administering 200ml would take 2 hours.
It is 2.5 molar. The reason for this is that molarity means moles per litre. You have to multiply by 5 to get from 200ml to a litre, so you have to do the same with the moles.
The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.
Mayer reagent (for narcotic alkaloids) "... can be created by dissolving 1.358 grams of HgCl2 in 60 milliliters of water, and pouring that solution into a solution of 5 grams of KI in 10 milliliters of water." (quoted from patentstorm)
200mL equates to 2dL (deciliters).
Change 200mL into decimal.