1. Weigh 26, 298 g ultrapure NaCl dried at 110 0C for 30 min.
2. Transfer NaCl in a 1 L graduated cyllinder class A.
3. Add approx. 800 mL demineralized water.
3. Put the cyllinder in a thermostat and maintain 30 min at 20 0C.
5. Add demineralized water up to the mark of o,9 L.
6. Transfer in a clean bottle with stopper.
7. Add a label with necessary information.
1000 ppm Cl- = 1.0 gram per liter Cl- = 1.0 * [58.5 (gNaCl/mole NaCl)] / [35.5 (gCl-/mole NaCl)] = 1.65 g/L NaCl
CL-
Mixing the two chemicals lends H+ ions to the solution. The solution weakens as a result of acetate ion concentration. No other reactions occur.
The solution contain ions as: Zn2+, (NO)-3, Ba2+, Cl-. Any reaction.
[1 mL*10 mM + 4 mL*(50*2 mM Cl-) ] mmolCl- in [1+4] mL total solutionThis is 410 (mmol Cl-) / 5 (mL) = 82 mM Cl-
You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
1 L = 100 cl so 900 cl = 9 L
1000 ppm Cl- = 1.0 gram per liter Cl- = 1.0 * [58.5 (gNaCl/mole NaCl)] / [35.5 (gCl-/mole NaCl)] = 1.65 g/L NaCl
we will prepare thiokol rubber from 1,2 dichloroethane and sodiumpolysulphide.The reaction is:cl-CH2-CH2-cl + Na-S-S-Na + cl-CH2-CH2-cl--------------> -----(----CH2-CH2-S-S-CH2-CH2----)n--------
In solution acids do. Example. HCl (in solution)-> H + + Cl -
Hydrochloric acid solution
Sorry, I mean a HCl solution in water, not Cl.
yeet
The anion chloride (Cl-) from salt is corrosive in solution.
After dissociation in solution or when is melted.
CL-
A solution of Na+(sodium ions) and Cl-(chlorine ions) in water is brine.