Well you can't. Bismuth nitrate hydrolyses to form the insoluble oxynitrate and/or bismuth hydroxide depending on the conditions. It is soluble in nitric acid and hydrolyses at around pH0
To prepare a 2 ppm solution of nickel nitrate, you would dissolve 2 grams of nickel nitrate in enough water to make 1 liter of solution. This will result in a solution where there are 2 parts of nickel nitrate for every 1 million parts of water.
To prepare a 40.0% lithium nitrate solution, 60mL of the solution would be solvent (water) and 90mL would be solute (lithium nitrate). Therefore, you would need 90mL of lithium nitrate to prepare 150mL of the 40.0% solution.
Dilute 1 mL of 0.5 M silver nitrate solution to a total volume of 1 L with water to make a 1 mM silver nitrate solution.
To prepare a sample of pure dry ammonium nitrate, dissolve ammonium nitrate in water to form a saturated solution, then allow the solution to cool and crystallize. Filter and dry the resulting crystals to obtain pure dry ammonium nitrate.
To prepare 0.02N silver nitrate solution, you need to dissolve 0.17g of silver nitrate (AgNO3) in 1 liter of solution to make a 0.02N solution. Measure the amount of silver nitrate accurately using a balance and dissolve it in distilled water to make the final volume up to 1 liter. Stir well to ensure complete dissolution.
Solution A: Bismuth nitrate (0.17g) in AcOH (2mL) and H2O (8mL) Solution B: KI (4g) in AcOH (10mL) and H2O (20mL) Mix Solns. A and B and dilute to 100mL with H2O.
To prepare a 2 ppm solution of nickel nitrate, you would dissolve 2 grams of nickel nitrate in enough water to make 1 liter of solution. This will result in a solution where there are 2 parts of nickel nitrate for every 1 million parts of water.
To prepare a 40.0% lithium nitrate solution, 60mL of the solution would be solvent (water) and 90mL would be solute (lithium nitrate). Therefore, you would need 90mL of lithium nitrate to prepare 150mL of the 40.0% solution.
Dilute 1 mL of 0.5 M silver nitrate solution to a total volume of 1 L with water to make a 1 mM silver nitrate solution.
To prepare a sample of pure dry ammonium nitrate, dissolve ammonium nitrate in water to form a saturated solution, then allow the solution to cool and crystallize. Filter and dry the resulting crystals to obtain pure dry ammonium nitrate.
To prepare a 0.1N Na2S2O3 solution, dissolve 24.98 grams of Na2S2O3·5H2O (sodium thiosulfate pentahydrate) in distilled water and dilute to 1 liter in a volumetric flask. This will give you a 0.1N (normal) solution of Na2S2O3.
Dissolve 16,99 g silver nitrate in 1 L demineralized water.
To prepare 0.02N silver nitrate solution, you need to dissolve 0.17g of silver nitrate (AgNO3) in 1 liter of solution to make a 0.02N solution. Measure the amount of silver nitrate accurately using a balance and dissolve it in distilled water to make the final volume up to 1 liter. Stir well to ensure complete dissolution.
To prepare one normal solution of potassium nitrate, you would dissolve 101.1 grams of potassium nitrate in enough water to make 1 liter of solution. This solution will have a concentration of 1 mole per liter, which is considered a normal solution. Make sure to use a balance to accurately measure the mass of potassium nitrate and a volumetric flask to ensure a final volume of 1 liter.
To prepare a 0.0141 N silver nitrate solution, you would need to weigh out the appropriate amount of silver nitrate based on its molar mass and dilute it in a known volume of water to make the final solution. Ensure to use a balance for accurate measurement and follow proper safety measures when handling chemicals.
To prepare a 1000 ppm nitrate solution from sodium nitrate, you would dissolve a specific amount of sodium nitrate in a known volume of water. For example, to prepare 1 liter of a 1000 ppm nitrate solution, you would dissolve 1 gram of sodium nitrate in 1 liter of water. Make sure to accurately weigh the sodium nitrate and dissolve it completely in the water to achieve the desired concentration.
To prepare a 500 ppm (parts per million) solution of lead nitrate, you would need to dissolve 500 grams of lead nitrate in 1 million grams (1,000,000 grams) of solution. The specific weight of lead nitrate would depend on its molar mass and density. It is more common to express concentrations in terms of molarity (moles per liter) rather than ppm for making solutions.