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∆G = ∆H - T∆S and ∆G has to be negative for the reaction to be spontaneous. So, ultimately the effect of temperature will depend on the value of ∆H. If ∆H is negative, and ∆S is positive, then temperature won't matter, and reaction will be spontaneous. If ∆H is positive, and ∆S is positive, then a high temperature will favor spontaneity. If ∆H is negative and ∆S is negative, then a low temperature will favor spontaneity. So, the answer to your question is the higher the temperature the more likely the reaction will occur spontaneously.

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How will the temperature affect the spontaneity of a reaction with positive h and s?

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For a reaction with a positive enthalpy change (ΔH > 0) and a positive entropy change (ΔS > 0), the spontaneity is influenced by temperature through the Gibbs free energy equation: ΔG = ΔH - TΔS. As temperature increases, the TΔS term becomes larger, which can make ΔG more negative, thereby favoring spontaneity. Therefore, at higher temperatures, the reaction is more likely to be spontaneous, while at lower temperatures, it may not be spontaneous.


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∆G = ∆H - T∆S and for it to be spontaneous, ∆G should be negative. If both ∆H and ∆S are positive, in order to get a negative ∆H, the temperature needs to be elevated in order to make the ∆S term greater than the ∆H term. So, I guess the answer would be "the higher the temperature, the more likely will be the spontaneity of the reaction."


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Doubles it