To find the number of Br atoms in 2.50 g of Br, you first need to convert grams to moles using the molar mass of Br. Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to atoms. Remember to check the molar mass of Br to ensure accurate calculations.
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There are 1.15 x 10^21 atoms in 0.220 g of P2O5.
The molar mass of PbBr2 is 367.008 g/mol
To find the number of atoms in 0.23 g of lead (Pb), you first need to determine the number of moles using the molar mass of lead. Lead has a molar mass of approximately 207.2 g/mol. Then use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
There are a total of 2 moles of anions in 2.50 g of MgBr2. Each formula unit of MgBr2 contains 2 moles of anions (Br-). The molar mass of MgBr2 is 184.113 g/mol, so 2.50 g is equivalent to 0.0136 moles, and therefore 0.0136 moles * 2 moles = 0.0272 moles of anions.
To find the grams of bromine (Br) in 595 g of calcium bromide (CaBr2), first determine the molar mass of CaBr2. The molar mass is approximately 40.08 g/mol for Ca and 79.90 g/mol for Br, giving a total of about 199.89 g/mol for CaBr2. Since there are two bromine atoms in each formula unit, the mass of bromine in CaBr2 is about 159.80 g (2 × 79.90 g). Thus, the mass of Br in 595 g of CaBr2 can be calculated as follows: (159.80 g Br / 199.89 g CaBr2) × 595 g CaBr2 ≈ 477.23 g of Br.
The standard atomic weight of platinum is 195,084 g.195,084 g-------------------------------1 mol250 g-------------------------------------x molx = 250/195,084 = 1,28 mol platinum
7,61 g LiBr contain 6,99 g Br.6,99 g Br is 0,087 moles.
445 g
250 g = about 0.55116 pounds.
To find out how many 250 g packets make 1 kg, you can divide 1000 g by 250 g. This calculation shows that 1 kg is equal to 4 packets of 250 g. Therefore, you need 4 packets of 250 g to make 1 kg.
250 g = 0.25 kgTo convert from g to kg, divide by 1000.
250 mg = 0.25 g
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49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
1 tonne = 1,000,000 g ⇒ 1 tonne ÷ 250 g = 1,000,000 g ÷ 250 g = 4,000
6,687.1023 chlorine atoms