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2.50 g MgBr2 x 1 mole MgBr2/184 g x 2 mole Br/mole MgBr2 = 0.0272 moles Br^-
0.0272 moles Br^- x 6.02x10^23 anions/mole = 1.6x10^22 anions
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∙ 8y ago
There are a total of 2 moles of anions in 2.50 g of MgBr2. Each formula unit of MgBr2 contains 2 moles of anions (Br-). The molar mass of MgBr2 is 184.113 g/mol, so 2.50 g is equivalent to 0.0136 moles, and therefore 0.0136 moles * 2 moles = 0.0272 moles of anions.
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How many anions are there in 3.50 g of MgBr2?
There are 0.021 moles of MgBr2 in 3.50 g. Since MgBr2 contains 2 bromide ions per formula unit, there are 0.042 moles of Br- ions. So, there are 0.042 * 6.022 x 10^23 = 2.53 x 10^22 Br- ions in 3.50 g of MgBr2.
How many moles of anions are in 37.4 g of AlF3?
To find the number of moles of anions in 37.4 g of AlF3, we first need to calculate the molar mass of AlF3. Aluminum (Al) has a molar mass of 26.98 g/mol, and fluorine (F) has a molar mass of 19.00 g/mol. So, the molar mass of AlF3 is 26.98 + (3 * 19.00) = 83.98 g/mol. Therefore, the number of moles of AlF3 in 37.4 g is 37.4 g / 83.98 g/mol = 0.445 moles. Since there are 3 fluoride ions (anions) in each formula unit of AlF3, the number of moles of anions in 37.4 g of AlF3 is 0.445 moles * 3 = 1.34 moles.
What is the percent composition of a compound containing 32.0 g of bromine and 4.9 g of magnesium?
To find the percent composition, first calculate the molar mass of the compound, then divide the mass of each element by the molar mass and multiply by 100 to get the percent composition. The molar mass of MgBr2 is 184.11 g/mol. Percent composition of bromine: (32.0 g Br / 184.11 g) x 100 = 17.38% Percent composition of magnesium: (4.9 g Mg / 184.11 g) x 100 = 2.67%
How many moles are there in 250 g of CaCO3?
To find the number of moles in 250 g of CaCO3, divide the given mass by the molar mass of CaCO3. The molar mass of CaCO3 is 100.09 g/mol. So, 250 g ÷ 100.09 g/mol ≈ 2.50 moles of CaCO3.
0.25 g to mg?
0.25 g is equal to 250 mg, as there are 1000 milligrams (mg) in one gram.
How many anions are there in 3.50 g of MgBr2?
There are 0.021 moles of MgBr2 in 3.50 g. Since MgBr2 contains 2 bromide ions per formula unit, there are 0.042 moles of Br- ions. So, there are 0.042 * 6.022 x 10^23 = 2.53 x 10^22 Br- ions in 3.50 g of MgBr2.
What is the mass of 7 moles of MgBr2?
The molar mass of MgCl2 = 95.211 g/mol
How many moles of anions are in 38.8 g of AlF3?
1.39 moles
How many pounds in 250 grams?
250 g = about 0.55116 pounds.
How many kg equals 250 g?
250 g = 0.25 kgTo convert from g to kg, divide by 1000.
How many grams are in 250 mg?
250 mg = 0.25 g
How many times does 250g go into 1 ton?
1 tonne = 1,000,000 g ⇒ 1 tonne ÷ 250 g = 1,000,000 g ÷ 250 g = 4,000
How many kilograms are there in 48 250 grams?
48 250 g = 48.25 kgTo convert from g to kg, divide by 1000.
How many moles are in 250 g iron (III) oxide?
250 g iron (III) oxide is equal to 1,565 moles.
How many kg are in 250 g?
250 g = 0.25 kgTo convert from g to kg, divide by 1000.
250 g equals how many ounces of weight?
250 grams = 8.81849049 ounces
How many 250 g packets made 10 kg?
40 packets of 250 g each can be made from 10 kg. Calculation below:250 g = 0.25 kg10 kg / 0.25 kg = 40OR10 kg = 10 000 g10 000 g / 250 g = 40
