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The molar mass of MgCl2 = 95.211 g/mol

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How many anions are there in 2.50 g of MgBr2?

There are a total of 2 moles of anions in 2.50 g of MgBr2. Each formula unit of MgBr2 contains 2 moles of anions (Br-). The molar mass of MgBr2 is 184.113 g/mol, so 2.50 g is equivalent to 0.0136 moles, and therefore 0.0136 moles * 2 moles = 0.0272 moles of anions.


How many moles of bromide ions are present in 750.0 mL of 1.35 M MgBr2?

There are 1.35 moles of MgBr2 in 1 L of solution, which corresponds to 2 moles of bromide ions. Therefore, in 750.0 mL of 1.35 M MgBr2 solution, there will be 1.0125 moles of bromide ions.


How many moles are equivalent to 3.6x1024 formula units of MgBr2?

The answer is 5,978 moles.


What is the mass of 7 moles of argon?

Mass of 1mole of Argon is 39.95g. So, The mass of 7 moles of Argon is 39.95x7= 279.65g.


How many anions are there in 3.50 g of MgBr2?

There are 0.021 moles of MgBr2 in 3.50 g. Since MgBr2 contains 2 bromide ions per formula unit, there are 0.042 moles of Br- ions. So, there are 0.042 * 6.022 x 10^23 = 2.53 x 10^22 Br- ions in 3.50 g of MgBr2.


What is the Molarity of a substance that contains 4.13 grams of magnesium bromide in 845 liters of a solution?

Molarity= mols/ L So, take 4.13g MgBr2 ( because Mg has a +2 charge and Bromide has a +1 charge) and divide it by 184.1 g MgBr2 which gives you .022 mols of MgBr2 then you divide .022 by 845 which gives you 2.65 M Molarity = 2.65M


How many ions does MgBr2 have?

One formula unit of MgBr2 has three ions; one Mg2+ ion and two Br- ions. One mole of MgBr2 formula units has one mole of Mg2+ ions and two moles of Br- ions, for a total of three moles of ions.


Formula for magnesium bromide?

The chemical formula of magnesium dibromide is MgBr2.


What is the mass of 7050 mol of uranium?

The mass of 7 050 moles of natural uranium is 238,02891 x 7 050.


How many grams are in 1.11 moles of manganese sulfate Mn3SO47?

To calculate the number of grams in 1.11 moles of manganese sulfate (Mn3(SO4)7), you need to find the molar mass of the compound. The molar mass of Mn3(SO4)7 is approximately 678.88 g/mol. Therefore, 1.11 moles of Mn3(SO4)7 would be equal to 1.11 moles x 678.88 g/mol ≈ 753.38 grams.


How many moles of gold are in 3.60x10-5g of gold?

To find the number of moles of gold, first calculate the molar mass of gold, which is 197 g/mol. Then, divide the given mass of gold by the molar mass to find the number of moles. In this case, 3.60x10-5g ÷ 197 g/mol ≈ 1.83x10-7 moles of gold.


How is the number of moles determined from a known mass?

Number of moles = Total mass/Molar mass