The molar mass of MgCl2 = 95.211 g/mol
The answer is 5,978 moles.
To find the mass of 7 moles of water (H₂O), first note that the molar mass of water is approximately 18 grams per mole. Therefore, the mass of 7 moles of water can be calculated by multiplying the number of moles by the molar mass: 7 moles × 18 g/mol = 126 grams. Thus, the mass of 7 moles of H₂O is 126 grams.
Molarity= mols/ L So, take 4.13g MgBr2 ( because Mg has a +2 charge and Bromide has a +1 charge) and divide it by 184.1 g MgBr2 which gives you .022 mols of MgBr2 then you divide .022 by 845 which gives you 2.65 M Molarity = 2.65M
The chemical formula of magnesium dibromide is MgBr2.
To convert grams to moles, you need to know the molar mass of the substance. Divide the given mass in grams by the molar mass to find the number of moles. This calculation is done using the formula: moles = grams / molar mass.
There are a total of 2 moles of anions in 2.50 g of MgBr2. Each formula unit of MgBr2 contains 2 moles of anions (Br-). The molar mass of MgBr2 is 184.113 g/mol, so 2.50 g is equivalent to 0.0136 moles, and therefore 0.0136 moles * 2 moles = 0.0272 moles of anions.
There are 1.35 moles of MgBr2 in 1 L of solution, which corresponds to 2 moles of bromide ions. Therefore, in 750.0 mL of 1.35 M MgBr2 solution, there will be 1.0125 moles of bromide ions.
The answer is 5,978 moles.
Mass of 1mole of Argon is 39.95g. So, The mass of 7 moles of Argon is 39.95x7= 279.65g.
There are 0.021 moles of MgBr2 in 3.50 g. Since MgBr2 contains 2 bromide ions per formula unit, there are 0.042 moles of Br- ions. So, there are 0.042 * 6.022 x 10^23 = 2.53 x 10^22 Br- ions in 3.50 g of MgBr2.
Molarity= mols/ L So, take 4.13g MgBr2 ( because Mg has a +2 charge and Bromide has a +1 charge) and divide it by 184.1 g MgBr2 which gives you .022 mols of MgBr2 then you divide .022 by 845 which gives you 2.65 M Molarity = 2.65M
One formula unit of MgBr2 has three ions; one Mg2+ ion and two Br- ions. One mole of MgBr2 formula units has one mole of Mg2+ ions and two moles of Br- ions, for a total of three moles of ions.
The chemical formula of magnesium dibromide is MgBr2.
The mass of 7 050 moles of natural uranium is 238,02891 x 7 050.
To calculate the number of grams in 1.11 moles of manganese sulfate (Mn3(SO4)7), you need to find the molar mass of the compound. The molar mass of Mn3(SO4)7 is approximately 678.88 g/mol. Therefore, 1.11 moles of Mn3(SO4)7 would be equal to 1.11 moles x 678.88 g/mol ≈ 753.38 grams.
To find the number of moles of gold, first calculate the molar mass of gold, which is 197 g/mol. Then, divide the given mass of gold by the molar mass to find the number of moles. In this case, 3.60x10-5g ÷ 197 g/mol ≈ 1.83x10-7 moles of gold.
Number of moles = Total mass/Molar mass