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How many anions are there in 2.50 g of MgBr2?
There are a total of 2 moles of anions in 2.50 g of MgBr2. Each formula unit of MgBr2 contains 2 moles of anions (Br-). The molar mass of MgBr2 is 184.113 g/mol, so 2.50 g is equivalent to 0.0136 moles, and therefore 0.0136 moles * 2 moles = 0.0272 moles of anions.
How many moles of anions are in 37.4 g of AlF3?
To find the number of moles of anions in 37.4 g of AlF3, we first need to calculate the molar mass of AlF3. Aluminum (Al) has a molar mass of 26.98 g/mol, and fluorine (F) has a molar mass of 19.00 g/mol. So, the molar mass of AlF3 is 26.98 + (3 * 19.00) = 83.98 g/mol. Therefore, the number of moles of AlF3 in 37.4 g is 37.4 g / 83.98 g/mol = 0.445 moles. Since there are 3 fluoride ions (anions) in each formula unit of AlF3, the number of moles of anions in 37.4 g of AlF3 is 0.445 moles * 3 = 1.34 moles.
What is the percent composition of a compound containing 32.0 g of bromine and 4.9 g of magnesium?
Total mass of MgBr2- 36.9 g Mass of Br 32.0 / total mass 36.9 = .867 = 86.7% Mass of Mg 4.9 / 36.9 = .133 = 13.3% There is 86.7% of Bromine and 13.3% of Magnesium in the compound MgBr2
How many grams of iron are in 350 Mg of iron?
There are 0.35 grams of iron in 350 mg. To convert milligrams (mg) to grams (g), you can divide by 1000.
What is the mass of carbon found in 350 grams of C2H6?
To find the mass of carbon in C2H6, we first need to calculate the molar mass of C2H6. Carbon has a molar mass of 12 g/mol, and hydrogen has a molar mass of 1 g/mol. The molar mass of C2H6 is (212) + (61) = 30 g/mol. The mass of carbon in 350 grams of C2H6 is then (2*12)/30 * 350 = 140 grams.
How many anions are there in 2.50 g of MgBr2?
There are a total of 2 moles of anions in 2.50 g of MgBr2. Each formula unit of MgBr2 contains 2 moles of anions (Br-). The molar mass of MgBr2 is 184.113 g/mol, so 2.50 g is equivalent to 0.0136 moles, and therefore 0.0136 moles * 2 moles = 0.0272 moles of anions.
What is the mass of 7 moles of MgBr2?
The molar mass of MgCl2 = 95.211 g/mol
How many moles of anions are in 38.8 g of AlF3?
1.39 moles
How many ounces in 350 gramms?
350 g = 12.3458 oz350 g = 12.3458 oz350 g = 12.3458 oz350 g = 12.3458 oz350 g = 12.3458 oz350 g = 12.3458 oz
How many moles of carbon monoxide are in 350 g sample?
350 g sample of CO contain 12,49 moles.
How many oz are 350 g?
That is 12.346 ounces
How many moles of anions are in 37.4 g of AlF3?
To find the number of moles of anions in 37.4 g of AlF3, we first need to calculate the molar mass of AlF3. Aluminum (Al) has a molar mass of 26.98 g/mol, and fluorine (F) has a molar mass of 19.00 g/mol. So, the molar mass of AlF3 is 26.98 + (3 * 19.00) = 83.98 g/mol. Therefore, the number of moles of AlF3 in 37.4 g is 37.4 g / 83.98 g/mol = 0.445 moles. Since there are 3 fluoride ions (anions) in each formula unit of AlF3, the number of moles of anions in 37.4 g of AlF3 is 0.445 moles * 3 = 1.34 moles.
What is the balance formula for Hydrobromic acid and magnesium sulfite?
So far I come up with: HBr (aq) + MgSO3 (s) --> H2SO3 (aq) + MgBr2 (??)
How many g of dextrose are found in 350 ml of D10W?
35
How many moles of anions are in 33.4 g of AlF3?
molar mass AlF3 = 83.98 g/mole33.4 g AlF3 x 1 mole/83.98 g = 0.398 molesEach mole of AlF3 contains 3 moles of F- anions, because AlF3 ==> Al^3+ + 3F^-.Thus, moles of anions = 3 x 0.398 = 1.19 moles of anions
What is the percent composition of a compound containing 32.0 g of bromine and 4.9 g of magnesium?
Total mass of MgBr2- 36.9 g Mass of Br 32.0 / total mass 36.9 = .867 = 86.7% Mass of Mg 4.9 / 36.9 = .133 = 13.3% There is 86.7% of Bromine and 13.3% of Magnesium in the compound MgBr2
How many teaspoons in 350g?
This question is impossible to answer without knowing what product is to be measured. For example, you'll get many more TBL from 350 g of flour than you would from 350 g of salt.
