answersLogoWhite

0

molar mass AlF3 = 83.98 g/mole33.4 g AlF3 x 1 mole/83.98 g = 0.398 moles

Each mole of AlF3 contains 3 moles of F- anions, because AlF3 ==> Al^3+ + 3F^-.

Thus, moles of anions = 3 x 0.398 = 1.19 moles of anions

User Avatar

Wiki User

7y ago

What else can I help you with?

Continue Learning about Earth Science

When 1 gram of liquid water at 0 degrees celsius freezes to form ice how many total joules of heat are lost by the water?

a change from liquid to solid or solid to liquid will require the use of the formula of Heat of Fusion , q=mHf where m is the mass and Hf = 334J/g, this is standard so you wont have to look for how it came about.In this case the m=5.00g so: q = m Hf q=(5.00g)(334 J/g) , you notice the grams will cancel out. q = 1670 J.


How much heat energy must be absorbed to completely melt 35 grams of h2o at o degrees?

it will be 11,700J since the formula would be: q=mHf=35g x 334 J/g= 11,700 J


How much heat must be lost by 2 grams of water at 0 degrees Celsius to change it to ice?

The heat lost by water at 0 degrees Celsius to change to ice is equal to the heat of fusion of water, which is about 334 joules per gram. So, for 2 grams of water, the heat loss would be 2 * 334 = 668 joules.


Years ago, a 20 kg block of ice was used daily in the home icebox to keep food cool The temperature of the ice was zero degrees Celsius when delivered How much heat did the ice absorb by the time it?

The heat absorbed by the ice can be calculated using the formula Q = m * L, where Q is the heat absorbed, m is the mass of the ice (20 kg), and L is the latent heat of fusion for ice (334 kJ/kg). Therefore, the ice absorbed 20 kg * 334 kJ/kg = 6680 kJ of heat as it melted.


How much heat energy must be absorbed to completely melt 35.0 grams of water at 0 degrees Celsius?

The heat energy required to melt a substance can be calculated using the formula: heat energy = mass * heat of fusion. For water, the heat of fusion is 334 J/g. So for 35.0 grams of water, the heat energy required to completely melt it is 35.0 g * 334 J/g = 11,690 J.