0.25 mole of H2O
The mass of NH3 mole = its molecular weight = 14 + 3 x 1 = 17 The mass of H2O mole = its molecular weight = 2 x 1 + 16 = 18 This means that one mole of NH3 weigh less than one mole of H2O
The molar mass of water (H2O) is approximately 18.015 grams per mole. The volume of one mole of water at standard temperature and pressure (STP) is about 18.0 milliliters.
To teach you how to do this problem: 1. Look at the Periodic Table. O =16 grams/mole, H =1.01 grams/mole 2. Calculate the Molecular Weight of Water. 1*O + 2*H: 16+2.02=18.02g/mole 3. Divide the mass of what you have by the Molecular Weight: 35.1g H2O/(18.02 g H2O/mole H2O) 4. The units g H2O cancel leaving you with mole H2O. 5. 35.1 grams H2O= 1.95 moles H2O
step 1; find # of moles 1.00*10^24 molecules x 1 mole of 6.02*10^23 molecules = 8.52*10^17 mole of H2O ( 1.0010*10^24 x 6.02*10^23 ) = 8.52*10^17 step 2 ; mass of H2O 8.52*10^17 mole x 18.02 grams per mole = 1.18*10^17 g H2O ( 8.52*10^17 x 18.02 ) = 1.18*10^17
0.25 mole of H2O
36g
The mass of NH3 mole = its molecular weight = 14 + 3 x 1 = 17 The mass of H2O mole = its molecular weight = 2 x 1 + 16 = 18 This means that one mole of NH3 weigh less than one mole of H2O
I assume KOH is limiting. Balanced equation. KOH + HCl -> KCl + H2O 0.400 moles KOH (1 mole H2O/1 mole KOH)(18.016 grams/1 mole H2O) = 7.21 grams water produced =====================
There are 0.0556 moles of H2O in 1.0 g of H2O. This calculation is obtained by dividing the given mass (1.0 g) by the molar mass of water (18.015 g/mol).
The molar mass of water (H2O) is approximately 18.015 grams per mole. The volume of one mole of water at standard temperature and pressure (STP) is about 18.0 milliliters.
one mole of any element is equals to its gam(Gram Atomic Mass) and one mole of any molecule is also equals to that molecules gram atomic mass. Lets calculate the gram molecular mass of water : h2o = 2 hydrogen atoms, 1 oxygen atom = 2 hydrogen x 1g (gram atomic mass of hydrogen) + 1 oxygen x 16g (gram atomic mass of oxygen) = 2 + 16 = 18g Therefore 1 mole of water contains 18grams.
To teach you how to do this problem: 1. Look at the Periodic Table. O =16 grams/mole, H =1.01 grams/mole 2. Calculate the Molecular Weight of Water. 1*O + 2*H: 16+2.02=18.02g/mole 3. Divide the mass of what you have by the Molecular Weight: 35.1g H2O/(18.02 g H2O/mole H2O) 4. The units g H2O cancel leaving you with mole H2O. 5. 35.1 grams H2O= 1.95 moles H2O
in order to find the mass of H20 you need the molar mass which is 18.01g/mol and to calculate the mass you just multiply by the number of moles. 18.01 * .20 = 3.60g
This information can help calculate the molar mass of water, which is 18 g/mol. By dividing the given mass of water by the number of moles, we get the molar mass.
To have 1 mole of H2O, you would need to weigh out approximately 18 grams of water (H2O). This is because 1 mole of water molecules (H2O) has a molar mass of about 18 grams/mol (2 grams/mol for hydrogen x 2 atoms + 16 grams/mol for oxygen).
The molar mass of H2O =(2 atoms H x 1.00794g/mol H) + (1 atom O x 15.9994g/mol O) = 18.0152g/mol H2O1 mole of H2O = 18.0152g H2O1 mole of H2O molecules = 6.022 x 1023 molecules H2OConvert molecules to moles.5.00 x 102g H2O molecules x (1mole H2O/6.022 x 1023 molecules H2O) =8.31 x 10-22 mole H2OConvert moles to grams.8.31 x 10-22 mole H2O x (18.0152g H2O/1mole H2O) = 1.50 x 10-20g H2OAnswer: The mass in grams of 5.00 x 102g H2O molecules = 1.50 x 10-20g H2O