No, it correspond to 18g.
the rule for solving amount of molecules is N(molecules)=6x10^23 x n(amount of mole) therefore there are 6x10^23 molecules in 1 mole of anything or in this case of H20
11.5 mole H2O (2 mole H/1 mole H2O)(6.022 X 10^23/1 mole H)(1 mole H/6.022 X 10^23) = 23.0 moles of H atoms
Since the molar mass (grams per mole) of H2O is 18.02, the grams of H2O in 4 moles is 72.08g.
im not really sure but here is what i think it is: 0.943 mole H2Ox 6.02x10^23 molecules H2O= 5.67686^23 molecules H2O sorry if its wrong.
The formula is: NaOH(aq) + HCl(aq) --> NaCl + H2O(l) So the ratio is: 1 : 1 : 1 : 1
The mass of NH3 mole = its molecular weight = 14 + 3 x 1 = 17 The mass of H2O mole = its molecular weight = 2 x 1 + 16 = 18 This means that one mole of NH3 weigh less than one mole of H2O
the rule for solving amount of molecules is N(molecules)=6x10^23 x n(amount of mole) therefore there are 6x10^23 molecules in 1 mole of anything or in this case of H20
36g
1 mole H2O = 18.015g H2O 1.57mol H2O x 18.015g H2O/1mol H2O = 28.3g H2O
11.5 mole H2O (2 mole H/1 mole H2O)(6.022 X 10^23/1 mole H)(1 mole H/6.022 X 10^23) = 23.0 moles of H atoms
Molar ratio's in this balanced equation: 1 + 2 --> 1 + 1 + 1 (H2O) respectively
0.25 mole of H2O
To have 1 mole of H2O, you would need to weigh out approximately 18 grams of water (H2O). This is because 1 mole of water molecules (H2O) has a molar mass of about 18 grams/mol (2 grams/mol for hydrogen x 2 atoms + 16 grams/mol for oxygen).
0.87 grams water (1 mole H2O/18.016 grams)(1 mole O/1 mole H2O)(6.022 X 1023/1 mole O) = 2.9 X 1022 atoms of oxygen --------------------------------------
Because they are.
I assume KOH is limiting. Balanced equation. KOH + HCl -> KCl + H2O 0.400 moles KOH (1 mole H2O/1 mole KOH)(18.016 grams/1 mole H2O) = 7.21 grams water produced =====================
Oxygen limits the reaction, so......Balanced equation. 2H2 + O2 -> 2H2O 7.89 mole H2O (1 mole O2/2 mole H2O) = 3.95 mole oxygen gas needed ------------------------------------------