No, it correspond to 18g.
the rule for solving amount of molecules is N(molecules)=6x10^23 x n(amount of mole) therefore there are 6x10^23 molecules in 1 mole of anything or in this case of H20
11.5 mole H2O (2 mole H/1 mole H2O)(6.022 X 10^23/1 mole H)(1 mole H/6.022 X 10^23) = 23.0 moles of H atoms
Since the molar mass (grams per mole) of H2O is 18.02, the grams of H2O in 4 moles is 72.08g.
im not really sure but here is what i think it is: 0.943 mole H2Ox 6.02x10^23 molecules H2O= 5.67686^23 molecules H2O sorry if its wrong.
The formula is: NaOH(aq) + HCl(aq) --> NaCl + H2O(l) So the ratio is: 1 : 1 : 1 : 1
The mass of NH3 mole = its molecular weight = 14 + 3 x 1 = 17 The mass of H2O mole = its molecular weight = 2 x 1 + 16 = 18 This means that one mole of NH3 weigh less than one mole of H2O
the rule for solving amount of molecules is N(molecules)=6x10^23 x n(amount of mole) therefore there are 6x10^23 molecules in 1 mole of anything or in this case of H20
36g
11.5 mole H2O (2 mole H/1 mole H2O)(6.022 X 10^23/1 mole H)(1 mole H/6.022 X 10^23) = 23.0 moles of H atoms
1 mole H2O = 18.015g H2O 1.57mol H2O x 18.015g H2O/1mol H2O = 28.3g H2O
The mole ratio of N2O5 to H2O depends on the balanced chemical equation for the reaction in which N2O5 decomposes or reacts. For example, in the decomposition of N2O5 into nitrogen dioxide (NO2) and water (H2O), the balanced equation is: 2 N2O5 → 4 NO2 + 2 H2O. In this case, the mole ratio of N2O5 to H2O is 1:1, as 2 moles of N2O5 produce 2 moles of H2O.
Molar ratio's in this balanced equation: 1 + 2 --> 1 + 1 + 1 (H2O) respectively
0.25 mole of H2O
To have 1 mole of H2O, you would need to weigh out approximately 18 grams of water (H2O). This is because 1 mole of water molecules (H2O) has a molar mass of about 18 grams/mol (2 grams/mol for hydrogen x 2 atoms + 16 grams/mol for oxygen).
0.87 grams water (1 mole H2O/18.016 grams)(1 mole O/1 mole H2O)(6.022 X 1023/1 mole O) = 2.9 X 1022 atoms of oxygen --------------------------------------
I assume KOH is limiting. Balanced equation. KOH + HCl -> KCl + H2O 0.400 moles KOH (1 mole H2O/1 mole KOH)(18.016 grams/1 mole H2O) = 7.21 grams water produced =====================
Because they are.