0.25 mole of H2O
45/94.2 is 0.4777 moles
To determine how many grams of zinc chloride (ZnCl₂) are needed to react with 45 grams of aluminum (Al), we first need to look at the balanced chemical equation for the reaction, which is: [ 2Al + 3ZnCl₂ \rightarrow 2AlCl₃ + 3Zn ] From the equation, 2 moles of aluminum react with 3 moles of zinc chloride. The molar mass of aluminum is approximately 27 g/mol, so 45 grams of aluminum corresponds to about 1.67 moles of Al. Thus, we need 2.5 moles of ZnCl₂ (since 1.67 moles Al will require 2.5 moles ZnCl₂). The molar mass of ZnCl₂ is about 136.3 g/mol, so 2.5 moles of ZnCl₂ would weigh approximately 340.75 grams.
To find the number of molecules in 45 grams of aluminum trifluoride (AlF₃), we first need to calculate the molar mass of AlF₃, which is approximately 26.98 g/mol (Al) + 3 × 19.00 g/mol (F) = 83.98 g/mol. Next, we can determine the number of moles in 45 grams by dividing the mass by the molar mass: 45 g / 83.98 g/mol ≈ 0.536 moles. Finally, using Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol), we find the number of molecules: 0.536 moles × (6.022 \times 10^{23}) molecules/mol ≈ (3.22 \times 10^{23}) molecules of AlF₃.
The density of the material is its mass divided by its volume. In this case, the density would be 180 grams / 45 mL = 4 grams/mL.
The molecular mass of fluorine gas, F2 is 2(19.0) = 38.0Amount of F2 = mass of sample/molar mass = 9.5/38.0 = 0.25mol There are 0.25 moles of fluorine in a 9.5g pure sample.
To calculate the number of grams in 2.50 moles of H2O, you first need to know the molar mass of water (H2O), which is approximately 18.015 g/mol. Then, you can use the formula: grams = moles x molar mass. So, 2.50 moles of H2O is equivalent to 45.04 grams (2.50 moles x 18.015 g/mol).
45 grams H20 x (1 mole H20/18 grams H2O) x (6.02E23 molecules H20/1 mole H2O) the grams H2O and moles H2O cancel out. When you punch it into your calculator, the answer comes out to: =1.505E24 molecules H2O
45/94.2 is 0.4777 moles
First of all we convert the mass of leadto moles. Using the equation moles = mass(g) / Ar (Realtive atomic Mass)_. Mass( g) = 45 g Ar =~ 207 (Periodic Table). Hence moles(Pb) = 45 x 207 Moles (Pb) = 9315 moles. Next using the Avogadro number. 1 moles(of A SUBSTANCE) contains 6.022 x 10^(23) atoms. Hence number of atoms in 9315 moles = 9315 x 6.022 x 10^(23) = 5.61 x 10^(27) atoms. As a 'silly' number. 5,610,000,000,000,000,000,000,000,000 atoms.
45mL of plain water has a mass of about 45 grams.
To find the number of molecules in 45 grams of aluminum trifluoride (AlF₃), we first need to calculate the molar mass of AlF₃, which is approximately 26.98 g/mol (Al) + 3 × 19.00 g/mol (F) = 83.98 g/mol. Next, we can determine the number of moles in 45 grams by dividing the mass by the molar mass: 45 g / 83.98 g/mol ≈ 0.536 moles. Finally, using Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol), we find the number of molecules: 0.536 moles × (6.022 \times 10^{23}) molecules/mol ≈ (3.22 \times 10^{23}) molecules of AlF₃.
45 g water are obtained.
45 grams
all i know is that it is 45-50 grams in weight. not mass
The density of the material is its mass divided by its volume. In this case, the density would be 180 grams / 45 mL = 4 grams/mL.
The molecular mass of fluorine gas, F2 is 2(19.0) = 38.0Amount of F2 = mass of sample/molar mass = 9.5/38.0 = 0.25mol There are 0.25 moles of fluorine in a 9.5g pure sample.
To find the number of moles in 55g of lithium chloride, we first need to calculate the molar mass of lithium chloride, which is approximately 42.39 g/mol. Then, we divide the mass given (55g) by the molar mass to get moles. Therefore, 55g of lithium chloride is approximately 1.30 moles.