The mole ratio of N2O5 to H2O depends on the balanced chemical equation for the reaction in which N2O5 decomposes or reacts. For example, in the decomposition of N2O5 into nitrogen dioxide (NO2) and water (H2O), the balanced equation is: 2 N2O5 → 4 NO2 + 2 H2O. In this case, the mole ratio of N2O5 to H2O is 1:1, as 2 moles of N2O5 produce 2 moles of H2O.
First write the equation out without coefficients unless you're given them __N2(g)+__O2(g)-->__N2O5(g) Then balance the equation, making sure that the products equal the reactants. Your answer should have 4 moles of N and 10 moles of O on each side. 2N2(g)+5O2(g)-->2N2O5
To determine the mole ratio of O2 to C4H9OH, we need to look at the balanced chemical equation for the combustion of butanol (C4H9OH). The balanced equation is: [ C4H9OH + 6 O2 \rightarrow 4 CO2 + 5 H2O. ] From the equation, the mole ratio of O2 to C4H9OH is 6:1. Thus, for every mole of butanol, six moles of oxygen are required.
The mole ratio of H2S to Ag2S can be derived from the balanced chemical equation for the reaction between hydrogen sulfide (H2S) and silver sulfide (Ag2S). The balanced equation is typically represented as 2 H2S + Ag2S → 4 Ag + 2 H2O + 2 S. From this equation, the mole ratio of H2S to Ag2S is 2:1.
To determine the ratio of moles of Mo(NO3)2•5H2O (molybdenum(II) nitrate pentahydrate), you typically need to consider the number of moles of the compound itself. In this case, 1 mole of Mo(NO3)2•5H2O contains 1 mole of Mo, 2 moles of NO3, and 5 moles of H2O. Therefore, the ratio of moles can be expressed as 1:2:5 for Mo:NO3:H2O respectively.
The mass of NH3 mole = its molecular weight = 14 + 3 x 1 = 17 The mass of H2O mole = its molecular weight = 2 x 1 + 16 = 18 This means that one mole of NH3 weigh less than one mole of H2O
Molar mass of N2O5 = (2x14.007) + (5x15.999) = 28.014 + 79.995 = 108.009 g/mole.
The acid form of N2O5 is nitric acid.
These ratios are not identical. In N2O5 the ratio is 2/5. In NO2 the ratio is 1/2.
The formula is: NaOH(aq) + HCl(aq) --> NaCl + H2O(l) So the ratio is: 1 : 1 : 1 : 1
Molar ratio's in this balanced equation: 1 + 2 --> 1 + 1 + 1 (H2O) respectively
First write the equation out without coefficients unless you're given them __N2(g)+__O2(g)-->__N2O5(g) Then balance the equation, making sure that the products equal the reactants. Your answer should have 4 moles of N and 10 moles of O on each side. 2N2(g)+5O2(g)-->2N2O5
To determine the mole ratio of O2 to C4H9OH, we need to look at the balanced chemical equation for the combustion of butanol (C4H9OH). The balanced equation is: [ C4H9OH + 6 O2 \rightarrow 4 CO2 + 5 H2O. ] From the equation, the mole ratio of O2 to C4H9OH is 6:1. Thus, for every mole of butanol, six moles of oxygen are required.
The whole number mole ratio of calcium sulfate (CaSO4) to water (H2O) in the compound CaSO4·2H2O is 1:2. This means that for every one mole of calcium sulfate, there are two moles of water present.
N2O5 + H2O == HNO3 + HNO3 Usually written as N2O5 + H2O = 2HNO3 You have 2 x nitrogen in N2O5 , so 2 x nitrogen in the products, one each in the two molecules of nitric acid. You have 2 x hydrogen in H2O , so 2 x hydrogen in the products, one each in the two molecules of nitric acid. You have 5 oxygens in N2O5 + 1 oxygen in water making for 6 oxygens. These oxygen are equally shared ( 3 each) in the two nitric acid molecules. However, we do not write ' HNO3 + HNO3 ' in chemistry , but use a little bit of 'shorthand' and write it as ' 2HNO3 '. to indicate that there are two(2) molecules of nitric acid formed.
i think its 3/1 from a worksheet a) 3/1 b) 1/3 c) 2/3 d) 3/2
The mole ratio of H2S to Ag2S can be derived from the balanced chemical equation for the reaction between hydrogen sulfide (H2S) and silver sulfide (Ag2S). The balanced equation is typically represented as 2 H2S + Ag2S → 4 Ag + 2 H2O + 2 S. From this equation, the mole ratio of H2S to Ag2S is 2:1.
The molar ratio of hydrogen to oxygen in water (H2O) is 2:1. This means that for every 2 moles of hydrogen, there is 1 mole of oxygen.