Balanced equation first.
NaOH + HCl >> NaCl + H2O
Everything is one to one, so
1.222 moles HCl (1mole NaOH/1mole HCl)
= 1.222 moles NaOH
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
There is one mole of Na⁺ ions for every mole of NaCl. This is because each mole of NaCl dissociates into one mole of Na⁺ ions and one mole of Cl⁻ ions in solution.
Since Na2O is a 1:1 ratio with Na, if 2.80 moles of Na react, 2.80 moles of Na2O will be produced. To convert moles to grams, we use the molar mass of Na2O (61.98 g/mol) to find that 2.80 moles of Na2O is equal to 2.80 moles * 61.98 g/mol = 173.50 grams of Na2O.
Using the equation 2Na + 2HCl -> 2NaCl + H2, we can see that 2 moles of Na react with 2 moles of HCl to produce 1 mole of H2. Calculate moles of Na: 25g Na * 1 mol Na / 23g Na = 1.09 mol Na. Since the reaction is with excess HCl, the number of moles of H2 produced will be half the number of moles of Na, so it will be 0.545 moles of H2.
0.21705 moles. There are 22.9898 grams sodium in 1 mole.
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 2.5 moles Na+ and 2.5 moles Cl-, totaling 5 moles of ions altogether.
This depends on the concentration of sodium chloride in water.
Balanced equation. 4Na + O2 -> 2Na2O 10 moles Na (2 moles Na2O/4 moles Na) = 5.0 moles Na2O produced
When sodium (Na) and chlorine (Cl) react, sodium loses an electron to form a Na+ ion with a positive charge, and chlorine gains this electron to form a Cl- ion with a negative charge. As a result, Na becomes positively charged and Cl becomes negatively charged when they react.
There is one mole of Na⁺ ions for every mole of NaCl. This is because each mole of NaCl dissociates into one mole of Na⁺ ions and one mole of Cl⁻ ions in solution.
Since Na2O is a 1:1 ratio with Na, if 2.80 moles of Na react, 2.80 moles of Na2O will be produced. To convert moles to grams, we use the molar mass of Na2O (61.98 g/mol) to find that 2.80 moles of Na2O is equal to 2.80 moles * 61.98 g/mol = 173.50 grams of Na2O.
Using the equation 2Na + 2HCl -> 2NaCl + H2, we can see that 2 moles of Na react with 2 moles of HCl to produce 1 mole of H2. Calculate moles of Na: 25g Na * 1 mol Na / 23g Na = 1.09 mol Na. Since the reaction is with excess HCl, the number of moles of H2 produced will be half the number of moles of Na, so it will be 0.545 moles of H2.
The balanced chemical equation for the reaction between sodium and water is: 2 Na + 2 H2O -> 2 NaOH + H2 Since 2 moles of water are needed to react with 2 moles of sodium, 1 mole of water is needed to react with 1 mole of sodium. Therefore, 2.5 moles of sodium will require 2.5 moles of water for the reaction.
Because it ionizes into Na+ and Cl-, thus ONE mole or molecule of NaCl produces TWO moles or molecules, namely Na and Cl, thus i (the van't Hoff factor) is 2.
Sodium chloride is dissociated in water: NaCl------------Na+ + Cl-