0
1 mole K = 6.022 x 1023 atoms K
Convert known moles to atoms.
0.0671mol K X (6.022 x 1023 atoms K/1mol K) = 4.04 x 1022 atoms K
Wiki User
∙ 12y ago
Add your answer:
Earn +20 pts
How many grams in 1.90 moles of K?
The atomic mass of potassium is 39.10 g/mol. 1.90 mol K * (39.10 g K / 1 mol K) = 74.3 g K
How many moles are of H2O are needed to react completely with 7.54 mol of K?
7.54 mol of K
What is the average velocity of atoms in 1.50 mol of neon (a monatomic gas) at 278 K?
832
What is the average velocity of atoms in 1.00 mol of neon a monatomic gas at 288 K?
847 m/s
How many moles of KBr will be produced from 4.79 moles of BaBr2?
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
How many atoms of K in 2.77g of KCl?
2.77 g KCl * x moles KCl/ 74.5 g/mol 0.0372 mol KCl * 1 mol K/ 1 mol Cl = 0.0372 mol K 0.0372 mol K * 6.02*10^23 2.24*10^22 atoms K
How many atoms are in 0.0602 mol K?
0.0602 mole K x 6.02x10^23 atoms/mole = 3.62x10^22 atoms
How many grams in 1.90 moles of K?
The atomic mass of potassium is 39.10 g/mol. 1.90 mol K * (39.10 g K / 1 mol K) = 74.3 g K
Calculate the number of atoms in 0.551 g of potassium K?
0.551g* 1 mol/39.09g*6.022*1023/mol =0.0848*1023
How many grams of potassium are there in 7.20 mol of potassium atoms?
7.20 moles K x 39.1 g/mole = 281.52 g K = 282 g K (to 3 significant figures)
How many moles are of H2O are needed to react completely with 7.54 mol of K?
7.54 mol of K
What is the average velocity of atoms in 1.50 mol of neon (a monatomic gas) at 278 K?
832
How many moles of potassium are contained in 449g of potassium?
449 (g K) / 39.1 (g/mol K) = 11.5 mol K
What is the average velocity of atoms in 1.00 mol of neon a monatomic gas at 288 K?
847 m/s
How many atoms are there in 1.25 mol of silver?
you have m = 12.5g M = 107.9g/mol Na = 6.02x10^23atoms/mol = avagadros number N = ? atoms then the number of moles is n = m/M = N/Na gives N = mNa/M = 12.5*6.02x10^23 / 107.9 = 6.97 x 10^22 atoms
How many k ions ain 6.76 mol of K3PO4?
MW =3*39+1*31+4*16 = 212 in K3Po43 mol K+ ions produce. 1 mol weigh = 212 contain 3x6.023x10^23 K+ ions 6.76g contain = 6.76 x 3 moles K+ x 6.023x10^23 / 212 g/mol = 5.76x10^22
How many moles of KBr will be produced from 14.17 moles of BaBr2?
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
