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How many grams in 1.90 moles of K?
To convert from moles to grams, we need to use the molar mass of the element. The molar mass of potassium (K) is approximately 39.10 g/mol. So, for 1.90 moles of K, the mass would be 1.90 moles * 39.10 g/mol = 74.29 grams.
What is the value for G at 100 K if H 27 kJ mol and S 0.09 kJ molK?
G=18 kJ/mol
What is the value for G at 300 K if H 27 kJmol and S 0.09 kJmolK?
G = 0 kJ/mol
What is the mass of 0.806 mol of the element potassium (K) Answer in units of g.?
0,806 mol of the element potassium (K) is equal to 31,51 g.
How many grams of potassium are in 27.8 g of K2CrO7?
To find the grams of potassium in K2CrO7, first determine its molar mass. Potassium (K) has a molar mass of 39.10 g/mol, and K2CrO7 has two potassium atoms, so (39.10 g/mol) * 2 = 78.20 g/mol. Then, divide the mass of K2CrO7 by its molar mass to get the grams of potassium: (27.8 g) / (294.19 g/mol) ≈ 9.45 g of potassium.
How many atoms are in 0.0602 mol K?
0.0602 mole K x 6.02x10^23 atoms/mole = 3.62x10^22 atoms
How many atoms of K in 2.77g of KCl?
To find the number of K atoms in KCl, we first calculate the molar mass of KCl: 39.10 (K) + 35.45 (Cl) = 74.55 g/mol. Next, we determine the number of moles of KCl in 2.77g: 2.77g / 74.55 g/mol = 0.0371 mol. Since there is 1 K atom in 1 KCl molecule, the number of K atoms in 2.77g of KCl is the same as the number of moles of KCl, which is 0.0371 mol.
How many atoms are present in 3.8 mol of k?
To find the number of atoms in 3.8 moles of potassium (K), you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Multiply the number of moles by Avogadro's number: [ 3.8 , \text{mol} \times 6.022 \times 10^{23} , \text{atoms/mol} \approx 2.28 \times 10^{24} , \text{atoms}. ] Therefore, there are approximately (2.28 \times 10^{24}) atoms in 3.8 moles of potassium.
How many grams of potassium are there in 7.20 mol of potassium atoms?
7.20 moles K x 39.1 g/mole = 281.52 g K = 282 g K (to 3 significant figures)
How do you find the mass of a sample of 1.72 x 1023 atoms of potassium?
1 mole K atoms = 39.0983g K (atomic weight in grams)1 mole K atoms = 6.022 x 1023 atoms K (Avogadro's number)Convert known atoms to moles.1.72 x 1023 atoms K x (1mol K/6.022 x 1023 atoms K) = 0.286mol KConvert moles to mass in grams.0.286mol K x (39.0983g K/1mol K) = 11.2g K
Calculate the number of atoms in 0.551 g of potassium K?
To calculate the number of atoms in 0.551 g of potassium (K), you first need to convert the mass to moles using the molar mass of potassium (39.10 g/mol). Next, you use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Therefore, 0.551 g of potassium would contain approximately 7.1 x 10^22 atoms.
How many atoms are there in 1.25 mol of silver?
you have m = 12.5g M = 107.9g/mol Na = 6.02x10^23atoms/mol = avagadros number N = ? atoms then the number of moles is n = m/M = N/Na gives N = mNa/M = 12.5*6.02x10^23 / 107.9 = 6.97 x 10^22 atoms
How many grams in 1.90 moles of K?
To convert from moles to grams, we need to use the molar mass of the element. The molar mass of potassium (K) is approximately 39.10 g/mol. So, for 1.90 moles of K, the mass would be 1.90 moles * 39.10 g/mol = 74.29 grams.
How many k ions ain 6.76 mol of K3PO4?
MW =3*39+1*31+4*16 = 212 in K3Po43 mol K+ ions produce. 1 mol weigh = 212 contain 3x6.023x10^23 K+ ions 6.76g contain = 6.76 x 3 moles K+ x 6.023x10^23 / 212 g/mol = 5.76x10^22
What is the average velocity of atoms in 2.00 mol of neon at 308 K?
The root mean square velocity of atoms in a gas can be calculated using the formula: vrms = sqrt((3kT)/m), where k is the Boltzmann constant, T is the temperature in Kelvin, and m is the molar mass of the gas. For neon with a molar mass of 20.18 g/mol, the vrms at 308 K would be approximately 516 m/s.
What is the value for G at 100 K if H 27 kJ mol and S 0.09 kJ molK?
G=18 kJ/mol
What is the value for G at 300 K if H 27 kJmol and S 0.09 kJmolK?
G = 0 kJ/mol
