Best Answer

Study guides

☆☆

Q: How many grams in 1.90 moles of K?

Write your answer...

Submit

Still have questions?

Continue Learning about Chemistry

Molecular weight of potassium (K): 39.1 g/mole...Just divide 156 by the molecular weight to get moles:156/39.1 = 3.99 moles K

Atomic mass of potassium, K = 39.1 Amount of potassium is 156.4g sample = 156.4/39.1 = 4.00mol There are 4 moles of potassium in 156.4 grams of potassium.

Atomic mass of potassium, K = 39.1 Amount of K in 2.0g sample = 2.0/39.1 = 0.0512mol

I forget the easier way, so we do it this way. Use PV = nRT and find moles O2. (1 atm)(44.8 liters) = n(0.08206 L*atm/mol *K)(298.15 K) = 1.831 moles O2 1.831 moles O2 (32.0 grams/1 mole O2) = 58.6 grams of O2

The atomic weight of K is 39.098 and so 0.180 moles would be: 39.098 x 0.180 = 7.038 g to 3 decimal places.

Related questions

There are 39.0983 grams in one mole of K (potassium). a mole is a number. you cannot ask how many moles are in potassium. but you may ask how many moles of a certain substance are in potassium.

Molecular weight of potassium (K): 39.1 g/mole...Just divide 156 by the molecular weight to get moles:156/39.1 = 3.99 moles K

This problem requires potassium's atomic mass. Take the number of moles multiply it by the atomic mass. Going from grams to moles, you would divide instead. 3.00 mole K Ã— (39.1 grams) = 117.3 grams K

Divide mass by atomic mass: 0.98 (g K) / 39.1 (g/mol K) = 0.020 mol K

Atomic mass of potassium, K = 39.1 Amount of potassium is 156.4g sample = 156.4/39.1 = 4.00mol There are 4 moles of potassium in 156.4 grams of potassium.

Atomic mass of potassium, K = 39.1 Amount of K in 2.0g sample = 2.0/39.1 = 0.0512mol

can you help with this question

I forget the easier way, so we do it this way. Use PV = nRT and find moles O2. (1 atm)(44.8 liters) = n(0.08206 L*atm/mol *K)(298.15 K) = 1.831 moles O2 1.831 moles O2 (32.0 grams/1 mole O2) = 58.6 grams of O2

Potassium has atomic number 39.1.Amount of K in 284g sample = 284/39.1 = 7.26molThere are 7.26 moles of potassium in a 284g sample.

7.20 moles K x 39.1 g/mole = 281.52 g K = 282 g K (to 3 significant figures)

Use.PV = nRTTo get moles O2. ( 20.0o C = 293.15 Kelvin )(1.00 atm)(1120.0 L) = (X moles)(0.08206 L*atm/mol*K)(293.15 K)Moles = 1120.0/24.56= 45.60 moles O2-----------------------------------now,45.60 moles O2 (1 mole KO2/2 mole O2)(71.1 grams/1 mole KO2)= 1621 grams potassium oxide required=============================

The atomic weight of K is 39.098 and so 0.180 moles would be: 39.098 x 0.180 = 7.038 g to 3 decimal places.

People also asked