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The atomic weight of K is 39.098 and so 0.180 moles would be:
39.098 x 0.180 = 7.038 g to 3 decimal places.
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How many protons are in 4.78g of K?
4.78 grams K (1 mole K/39.10 grams)(6.022 X 1023/1 mole K)(19 protons/1 atom K) = 1.40 X 1024 protons in that mass potassium ============================
What is the mass of potassium chloride when 6.75 g of potassium reacts with an excess of chlorine gas?
Balanced equation and potassium limits and drives the reaction.2K + Cl2 -> 2KCl6.75 grams K (1 mole K/39.10 grams)(2 mole KCl/2 mole K)(74.55 grams /1 mole KCl)= 12.9 grams potassium chloride produced==============================
How many grams of KO2 would be required to produce 1120.0L of O2 at 20.0 degrees Celsius and 1.00atm?
Use.PV = nRTTo get moles O2. ( 20.0o C = 293.15 Kelvin )(1.00 atm)(1120.0 L) = (X moles)(0.08206 L*atm/mol*K)(293.15 K)Moles = 1120.0/24.56= 45.60 moles O2-----------------------------------now,45.60 moles O2 (1 mole KO2/2 mole O2)(71.1 grams/1 mole KO2)= 1621 grams potassium oxide required=============================
How many grams of potassium are in 24.1 g of K2Cr2O7?
The molecular weight of K2Cr2O7 is: 2(39.0983 g K/mole) + 2(51.9961 g Cr/mole) +7(15.9994 g O/mole) = 294.1846 g/mole thus 24.1 g of K2Cr2O7 is 0.08192 moles. Since it is 2(39.0983 g K/mole) that would mean you have 6.406 g of K (potassium)
What is the amount percentage of manganese in potassium permanganate KMnO4?
% by mole. There are six elements in KMnO4 only one is K so 1/6 which is 16.67% % by mass. Molar weight of K 39grams/mole. Molar weight of KMNO4 154 grams/mole so 39/154 =25%
How many protons are in 4.78g of K?
4.78 grams K (1 mole K/39.10 grams)(6.022 X 1023/1 mole K)(19 protons/1 atom K) = 1.40 X 1024 protons in that mass potassium ============================
What is the mass of potassium chloride when 6.75 g of potassium reacts with an excess of chlorine gas?
Balanced equation and potassium limits and drives the reaction.2K + Cl2 -> 2KCl6.75 grams K (1 mole K/39.10 grams)(2 mole KCl/2 mole K)(74.55 grams /1 mole KCl)= 12.9 grams potassium chloride produced==============================
How many grams of potassium are there in 7.20 mol of potassium atoms?
7.20 moles K x 39.1 g/mole = 281.52 g K = 282 g K (to 3 significant figures)
How many atoms are in 3.50 moles of calcium?
There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K. Therefore, 3.5 moles * 6.022E23 atoms/1 mole= 2.107E24
How do you find the mass of a sample of 1.72 x 1023 atoms of potassium?
1 mole K atoms = 39.0983g K (atomic weight in grams)1 mole K atoms = 6.022 x 1023 atoms K (Avogadro's number)Convert known atoms to moles.1.72 x 1023 atoms K x (1mol K/6.022 x 1023 atoms K) = 0.286mol KConvert moles to mass in grams.0.286mol K x (39.0983g K/1mol K) = 11.2g K
How many atoms are in 0.0602 mol K?
0.0602 mole K x 6.02x10^23 atoms/mole = 3.62x10^22 atoms
What is the molarity of a 5.00x 10 2ml solution containing 249g of k?
Molarity = moles of solute/Liters of solution some conversion needed 5.00 X 102 ml = 0.5 liters ------------------------------------- 249 grams K (1 mole K/39.10 grams = 6.37 moles potassium ------------------------------------------------------------------------------- Molarity = 6.37 mole K/0.5 Liters = 12.7 M K -----------------( as expected, highly concentrated solution )
How many grams of potassium are in 24.1 g of K2Cr2O7?
The molecular weight of K2Cr2O7 is: 2(39.0983 g K/mole) + 2(51.9961 g Cr/mole) +7(15.9994 g O/mole) = 294.1846 g/mole thus 24.1 g of K2Cr2O7 is 0.08192 moles. Since it is 2(39.0983 g K/mole) that would mean you have 6.406 g of K (potassium)
How many grams of KO2 would be required to produce 1120.0L of O2 at 20.0 degrees Celsius and 1.00atm?
Use.PV = nRTTo get moles O2. ( 20.0o C = 293.15 Kelvin )(1.00 atm)(1120.0 L) = (X moles)(0.08206 L*atm/mol*K)(293.15 K)Moles = 1120.0/24.56= 45.60 moles O2-----------------------------------now,45.60 moles O2 (1 mole KO2/2 mole O2)(71.1 grams/1 mole KO2)= 1621 grams potassium oxide required=============================
How many potassium atoms are in 0.0384 mole K?
0.0384 moles K x 6.02x10^23 atoms/mole = 2.31x10^22 atoms
How can you convert Meq to Mg?
fo potassium 60 mEq K = 60 millimoles 39.1 grams per mole ( 0.060moles) = 2.346 grams =2346 mg
What is the amount percentage of manganese in potassium permanganate KMnO4?
% by mole. There are six elements in KMnO4 only one is K so 1/6 which is 16.67% % by mass. Molar weight of K 39grams/mole. Molar weight of KMNO4 154 grams/mole so 39/154 =25%
