The Atomic Mass of potassium, K is 39.1.
This means that 1 mole of potassium has a mass of 39.1g.
Mass of 0.5mol of K = 0.5 x 39.1 = 19.6g
Moles of the soild = 1.78/ 208 = .00856 moles of H2O = 0.90/ 18 =.05 therefore number of moles of water for 1 mole of solid = .05/.00856 = approx 6
I mole of sulfur atoms is 32 g. Thus there are 300/32 moles in 300 g, i.e. 9.375 moles.
137.4 g First you need to calculate the molar mass of the molecule. Be = 9.01 g/mol C = 12.01 g/mol I = 126.9 g/mol Thus BeCI2 is equivalent to ( 9.01 + 12.01 + 2(126.9) ) g/mol or 274.82 g/mol. Then, using conversions, you multiply the amount you have by the molar mass so that: (.05 mol BeCI2)*(274.82 g/mol). The moles cancel out and you are left with a weight of 137.41 g.
.05 ounces = 1.41748 grams
0,0005 kg
Divide by 1000 to convert grams into kilograms
One kg = 1000 grams. So one gram is 10^-3 kilograms. One milli gram is 10^-3 gram = 10^-6 kg. Kilograms and grams are both the metric units of mass. So the answer in kg is 0.050
Yes.
56.69 1/2 grams in an oz
.05 grams. 50mg costs 50 bucks
the answer is 1.5
At low concentrations, normality and molarity are about the same. So figure out how many grams are in a mole of KOH: K-39, O-16, H-1, so 39+16+1=56g/mol. 0.05 moles would be 56(.05)=2.8g, so dissolve 2.8 grams of KOH in a liter of water and you're there.