The Atomic Mass of potassium, K is 39.1.
This means that 1 mole of potassium has a mass of 39.1g.
Mass of 0.5mol of K = 0.5 x 39.1 = 19.6g
To determine the number of moles in 300 grams of sulfur, you need to know the molar mass of sulfur. The molar mass of sulfur is 32.06 g/mol. You can calculate the number of moles by dividing the given mass by the molar mass: 300 g / 32.06 g/mol ≈ 9.35 moles.
The molar mass of the hydrated compound is 208 g/mol. To find the formula of the hydrate, we need to determine the molar mass of the anhydrous compound (XY) and subtract it from the total molar mass. With that information, we can calculate the molar mass of water in the hydrate and determine the ratio between XY and water molecules, giving us the formula of the hydrate.
137.4 g First you need to calculate the molar mass of the molecule. Be = 9.01 g/mol C = 12.01 g/mol I = 126.9 g/mol Thus BeCI2 is equivalent to ( 9.01 + 12.01 + 2(126.9) ) g/mol or 274.82 g/mol. Then, using conversions, you multiply the amount you have by the molar mass so that: (.05 mol BeCI2)*(274.82 g/mol). The moles cancel out and you are left with a weight of 137.41 g.
.05 ounces = 1.41748 grams
Divide by 1000 to convert grams into kilograms
0,0005 kg
One kg = 1000 grams. So one gram is 10^-3 kilograms. One milli gram is 10^-3 gram = 10^-6 kg. Kilograms and grams are both the metric units of mass. So the answer in kg is 0.050
56.69 1/2 grams in an oz
At low concentrations, normality and molarity are about the same. So figure out how many grams are in a mole of KOH: K-39, O-16, H-1, so 39+16+1=56g/mol. 0.05 moles would be 56(.05)=2.8g, so dissolve 2.8 grams of KOH in a liter of water and you're there.
Yes.
.05 grams. 50mg costs 50 bucks
50 mg is .05 gm