To find the number of atoms in 3.8 moles of potassium (K), you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Multiply the number of moles by Avogadro's number:
[ 3.8 , \text{mol} \times 6.022 \times 10^{23} , \text{atoms/mol} \approx 2.28 \times 10^{24} , \text{atoms}. ]
Therefore, there are approximately (2.28 \times 10^{24}) atoms in 3.8 moles of potassium.
The molecular mass of Zinc fluoride (ZnF2) is calculated by adding the atomic masses of zinc (Zn) and two fluorine (F) atoms. The atomic mass of zinc is approximately 65.38 g/mol, and the atomic mass of fluorine is about 18.99 g/mol. Therefore, the molecular mass of ZnF2 is approximately 102.36 g/mol.
All atoms of the specified data contain 38 protons, 38 electrons (assuming they are not ions), and 50 neutrons. They are atoms of the element Strontium.
The molar volume at 1 bar and 0 0C is 22,710 980(38) L/mol; each mol contain 6,022 140 857.10e23 molecules.
This atoms has an atomic number of 18 and an atomic mass of 38.
There are no 4s in number 38.
70 g/mol
There are a total of 38 atoms in 2Na2SO4 (sodium sulfate). This includes 4 sodium atoms, 2 sulfur atoms, and 8 oxygen atoms.
The molecular mass of Zinc fluoride (ZnF2) is calculated by adding the atomic masses of zinc (Zn) and two fluorine (F) atoms. The atomic mass of zinc is approximately 65.38 g/mol, and the atomic mass of fluorine is about 18.99 g/mol. Therefore, the molecular mass of ZnF2 is approximately 102.36 g/mol.
A month can have 30 , 31, or 28 days.in any of the situation 38 days would be present in 2 months.
All atoms of the specified data contain 38 protons, 38 electrons (assuming they are not ions), and 50 neutrons. They are atoms of the element Strontium.
Both are correct; the tenses are different (present perfect and past perfect).
The molar volume at 1 bar and 0 0C is 22,710 980(38) L/mol; each mol contain 6,022 140 857.10e23 molecules.
To determine the number of moles of fluorine present in 2.67 grams of nitrogen trifluoride (NF3), we first need to calculate the molar mass of NF3, which is 71.0 g/mol. Then we find the moles of NF3 in 2.67 g by dividing the mass by the molar mass: 2.67 g / 71.0 g/mol ≈ 0.038 moles. As there are three fluorine atoms in each molecule of NF3, there are 3 times more moles of fluorine: 0.038 moles NF3 x 3 = 0.114 moles of fluorine.
If the compound stated in the question exists, its gram molecular mass is (14 times the gram atomic mass of carbon) plus (9 times the gram atomic mass of hydrogen) + (15 times the gram atomic mass of chlorine), or about 709 grams. Therefore, the number of molecules of the compound in 1.0 gram of it is (1.0)(Avogadro's number)/709 or about 8.49 X 1020. Each molecule contains 14 (exact) carbon atoms, for a total of 1.2 X 1022 atoms of carbon, to the justified number of significant digits.
The number of moles of ethanol can be calculated as 496 g divided by the molar mass of ethanol, which is 46 g/mol. This equals 10.78 mol. The energy released can be calculated by multiplying the number of moles by the heat of vaporization: 10.78 mol * 38.6 kJ/mol = 416.25 kJ.
she is 18 in the serise but in the present shes 38
To calculate the number of moles of F2 molecules in 38g, we first need to determine the molar mass of F2, which is 38 grams/mol. Next, we can use the formula: moles = mass / molar mass. Therefore, the number of moles in 38g of F2 is 1 mole.