If the compound stated in the question exists, its gram molecular mass is (14 times the gram Atomic Mass of carbon) plus (9 times the gram atomic mass of hydrogen) + (15 times the gram atomic mass of chlorine), or about 709 grams. Therefore, the number of molecules of the compound in 1.0 gram of it is (1.0)(Avogadro's number)/709 or about 8.49 X 1020. Each molecule contains 14 (exact) carbon atoms, for a total of 1.2 X 1022 atoms of carbon, to the justified number of significant digits.
14..4 elements of carbon,10 of hydrogen 2nd Answer: Good grief! There are 2 elements in C4H10: Carbon and Hydrogen.
72.0 grams Carbon (1 mole C/12.01 grams)(6.022 X 10^23/1 mole C) = 3.61 X 10^24 atoms of carbon
Formula for alkanes:Number of H = 2 * number of C + 2So, using this formula, H = 2 * 10 + 2, which gives 22
The molecular formula of pyruvic acid is C3H4O3, which means it has 3 atoms of Carbon, 4 atoms of Hydrogen and 3 atoms of Oxygen. 10 atoms in total.
Using eight significant figures, there are 6.0221421 X 10^23 carbon atoms present in a mole of 12c.
Decane has 10 carbon atoms and 22 hydrogen atoms.
12 g of carbon will have 6.023 x 1023 atoms of carbon
Mass of 1 Helium atom is 4 amu and mass of 1 Carbon atom is 12 amu. So there are 10 helium atoms and 10 carbon atoms
The chemical formula for isodecane is C10H22, so one molecule of isodecane has 10 carbon atoms.
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There are 10 hydrogen atoms in an unbranched alkene with 1 double bond and 5 Carbon atoms
There are 5.0125 x 10^22 carbon atoms in 1 gram of carbon. 1 gram / 12.01 (GMW) x (6.02*10^23) (Avogadro's number) = 5.0125 x 10^22.
That is about the mole definition of Avogadro's number, so. 6.022 X 10^23 atoms of carbon
14..4 elements of carbon,10 of hydrogen 2nd Answer: Good grief! There are 2 elements in C4H10: Carbon and Hydrogen.
5 molecules of carbon dioxide will contain 5 carbon atoms (1 per molecule) and no hydrogen atoms as carbon dioxide contains only carbon and oxygen. The 5 molecules will contain a total of 10 oxygen atoms (2 per molecule).
We take the atomic mass of carbon to be 12.0Amount of carbon in 0.136g pure sample = 0.136/12.0 = 0.0113 The Avogadro's number is 6.02 x 10^23 Number of carbon atoms = 0.0113 x 6.02 x 10^23 = 6.82 x 10^21
72.0 grams Carbon (1 mole C/12.01 grams)(6.022 X 10^23/1 mole C) = 3.61 X 10^24 atoms of carbon