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If the compound stated in the question exists, its gram molecular mass is (14 times the gram Atomic Mass of carbon) plus (9 times the gram atomic mass of hydrogen) + (15 times the gram atomic mass of chlorine), or about 709 grams. Therefore, the number of molecules of the compound in 1.0 gram of it is (1.0)(Avogadro's number)/709 or about 8.49 X 1020. Each molecule contains 14 (exact) carbon atoms, for a total of 1.2 X 1022 atoms of carbon, to the justified number of significant digits.

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Q: How many atoms of Carbon are in 1.0 g of C14H9Cl15?
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