If the compound stated in the question exists, its gram molecular mass is (14 times the gram Atomic Mass of carbon) plus (9 times the gram atomic mass of hydrogen) + (15 times the gram atomic mass of chlorine), or about 709 grams. Therefore, the number of molecules of the compound in 1.0 gram of it is (1.0)(Avogadro's number)/709 or about 8.49 X 1020. Each molecule contains 14 (exact) carbon atoms, for a total of 1.2 X 1022 atoms of carbon, to the justified number of significant digits.
There are 20 atoms of oxygen in 10 molecules of carbon dioxide, as each molecule contains 2 oxygen atoms.
There are approximately 3.633 x 10^23 carbon atoms in 21.84 grams of carbon.
14..4 elements of carbon,10 of hydrogen 2nd Answer: Good grief! There are 2 elements in C4H10: Carbon and Hydrogen.
There are approximately 6 x 10^22 carbon atoms in 8g of pencil lead.
The answer is 6,2729.10e+26 carbon atoms.
Decane has 10 carbon atoms and 22 hydrogen atoms.
0.75 mole of carbon atoms (6.022 X 1023 /1 mole C x 0.75) = 4.52 X 1023 carbon atoms
Mass of 1 Helium atom is 4 amu and mass of 1 Carbon atom is 12 amu. So there are 10 helium atoms and 10 carbon atoms
There are 20 atoms of oxygen in 10 molecules of carbon dioxide, as each molecule contains 2 oxygen atoms.
There are approximately 3.633 x 10^23 carbon atoms in 21.84 grams of carbon.
The chemical formula for isodecane is C10H22, so one molecule of isodecane has 10 carbon atoms.
14..4 elements of carbon,10 of hydrogen 2nd Answer: Good grief! There are 2 elements in C4H10: Carbon and Hydrogen.
There are (6.022 \times 10^{23}) atoms in one mole of carbon. Therefore, in (1.0 \times 10^{-4}) moles of carbon, there would be (6.022 \times 10^{23} \times 1.0 \times 10^{-4} = 6.022 \times 10^{19}) carbon atoms.
There are approximately 6 x 10^22 carbon atoms in 8g of pencil lead.
There are 6.022 x1023 atoms of carbon per mole. So 2.85 * 6.022x1023 is the answer ... 1.72 x1024 atoms of carbon.
The answer is 6,2729.10e+26 carbon atoms.
There are 5.0125 x 10^22 carbon atoms in 1 gram of carbon. 1 gram / 12.01 (GMW) x (6.02*10^23) (Avogadro's number) = 5.0125 x 10^22.