1.28 x 10^21 atoms
The decomposition reaction for PCl5 is represented as follows: PCl5 (s) → PCl3 (g) + Cl2 (g). This reaction involves the breaking down of solid phosphorus pentachloride (PCl5) into gaseous phosphorus trichloride (PCl3) and chlorine gas (Cl2). The reaction is endothermic, requiring energy input to break the bonds within the PCl5 molecule.
The balanced chemical equation for the reaction is: P4 (s) + 6Cl2 (g) -> 4PCl3 (s). To find the limiting reactant, we need to calculate the moles of P4 and Cl2 using their molar masses first. Then, we compare the amounts of PCl3 that can be produced from each reactant, and the smaller value (in moles) will be the limiting reactant. Finally, convert the moles of PCl3 to grams.
There are 1.15 x 10^21 atoms in 0.220 g of P2O5.
To find the number of atoms in 0.23 g of lead (Pb), you first need to determine the number of moles using the molar mass of lead. Lead has a molar mass of approximately 207.2 g/mol. Then use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
To determine the number of atoms in 133 g of calcium, you first need to calculate the moles of calcium using the molar mass of calcium, which is 40.078 g/mol. Then, you use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. This will give you the number of atoms in 133 g of calcium.
The reaction will proceed to the right. 2 PCl3 will be consumed.
The decomposition reaction for PCl5 is represented as follows: PCl5 (s) → PCl3 (g) + Cl2 (g). This reaction involves the breaking down of solid phosphorus pentachloride (PCl5) into gaseous phosphorus trichloride (PCl3) and chlorine gas (Cl2). The reaction is endothermic, requiring energy input to break the bonds within the PCl5 molecule.
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
The balanced chemical equation for the reaction is: P4 (s) + 6Cl2 (g) -> 4PCl3 (s). To find the limiting reactant, we need to calculate the moles of P4 and Cl2 using their molar masses first. Then, we compare the amounts of PCl3 that can be produced from each reactant, and the smaller value (in moles) will be the limiting reactant. Finally, convert the moles of PCl3 to grams.
6,687.1023 chlorine atoms
The number of atoms of lead is 6,68.10e23.
5 g of sulfur contain 0,94.10e23 atoms.
The answer is 3.32*10^23 atoms
There are approximately 163,163 atoms of carbon in 0.020 g of carbon.
There are 1.15 x 10^21 atoms in 0.220 g of P2O5.
For plutonium 239: ca. 74,68.1023 atoms
The number of atoms is 28,099.10e23.