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How do you convert 2.76 g SE to moles SE?
To convert grams of selenium (Se) to moles, divide the given mass by the molar mass of selenium. The molar mass of selenium is approximately 78.97 g/mol. ( \dfrac{2.76 : g}{78.97 : g/mol} = 0.035 : mol : Se)
Which element Mo Se Na or Br contains the most moles of atoms in a 1.0 gram sample?
The element with the most moles of atoms in a 1.0 gram sample would be Mo (Molybdenum) as it has the highest molar mass among the given elements (95.94 g/mol). This means that 1.0 gram of Mo would contain the most moles of atoms compared to Se (Selenium), Na (Sodium), and Br (Bromine).
What does the Lewis dot structure look like for SeTe3?
The Lewis dot structure for SeTe3 will have selenium (Se) in the center bonded to three tellurium (Te) atoms. Each Te atom will be bonded to the Se atom by a single bond, and there will be lone pairs on the tellurium atoms to satisfy their octet.
What is the Lewis dot structure for Al2S3?
The chemical formula for aluminum selenide is Al2Se3. This is an ionic compound, so it is shown with 2 Al 2+ + 3 [Se] 2-. Around the Se are dot pairs on all four sides showing the complete transfer of electrons from the Al to the Se atoms.
What is the chemical formula for silver selenide?
The chemical formula for silver selenide is Ag₂Se. It is composed of two atoms of silver (Ag) and one atom of selenium (Se) in the compound.
How many atoms are there in 80.7 g of selenium?
Atomic mass Se = 78.96. So, atoms Se in 80.7g would be 80.7 g x 1mol/78.96g x 6.02x10^23atoms/mol = 6.15x10^23 atoms
Determine the mass in grams of 5.56x1024 atoms of selenium?
To determine the mass, you need to first find the molar mass of selenium, which is 78.971 g/mol. Then, divide the number of atoms by Avogadro's number to find the number of moles (5.56x10^24 atoms / 6.022x10^23 atoms/mol). Finally, multiply the number of moles by the molar mass to get the mass in grams (moles x molar mass).
What is the molar mass of Mn2Se7?
To calculate the molar mass of Mn₂Se₇, you need the atomic masses of manganese (Mn) and selenium (Se). The molar mass of Mn is approximately 54.94 g/mol, and for Se, it is about 78.96 g/mol. Thus, the molar mass of Mn₂Se₇ is calculated as follows: (2 × 54.94 g/mol) + (7 × 78.96 g/mol) = 109.88 g/mol + 552.72 g/mol = 662.60 g/mol. Therefore, the molar mass of Mn₂Se₇ is approximately 662.60 g/mol.
What 'SE' tells us how many atoms of each kind are there in a reaction?
The answer about SE is: symbol equation
How do you convert 2.76 g SE to moles SE?
To convert grams of selenium (Se) to moles, divide the given mass by the molar mass of selenium. The molar mass of selenium is approximately 78.97 g/mol. ( \dfrac{2.76 : g}{78.97 : g/mol} = 0.035 : mol : Se)
The mass in grams of 1.9 mol selenium?
1.9 mol Se ( 78.96 grams/1mol Se ) = 150.024 grams
A sample of Se weighs 20.5 grams will a sample of V that contains the same number of atoms weigh more or less than 20.5 grams?
A sample of Se weighs 20.5 grams. Will a sample of V that contains the same number of atoms weigh more or less than 20.5 grams? (more, less): _______Calculate the mass of a sample of V that contains the same number of atoms. _______ grams of VAnswer:Since the atomic weight of V is smaller than the atomic weight of Se, each atom will have a smallermass, and the sample will weigh less.Since the same number of moles will contain the same number of atoms, regardless of the element, it is only necessary to find the number of moles of Se in the 20.5 gram sample, and then to find the mass of the same number of moles of V.The atomic weight of Se is 79.0 g/mol1. Convert grams of Se to moles of Se:moles Se= 20.5 g Se1 mol = 0.260 mol Se79.0 gMultiply by moles per gram. Grams cancel out.The atomic weight of V is 50.9 g/mol2. To convert 0.260 moles of V to grams of V:grams V = 0.260 mol V50.9 g = 13.2 g V1 molMultiply by grams per mole. Moles cancel out.
How many atoms are in Cu2SeO4?
The chemical formula Cu2SeO4 indicates that there are two copper (Cu) atoms, one selenium (Se) atom, and four oxygen (O) atoms. To find the total number of atoms, you simply add these together: 2 (Cu) + 1 (Se) + 4 (O) = 7 atoms in total.
Which element Mo Se Na or Br contains the most moles of atoms in a 1.0 gram sample?
The element with the most moles of atoms in a 1.0 gram sample would be Mo (Molybdenum) as it has the highest molar mass among the given elements (95.94 g/mol). This means that 1.0 gram of Mo would contain the most moles of atoms compared to Se (Selenium), Na (Sodium), and Br (Bromine).
How many atoms does it to take to have a selenium and oxygen bond?
One atom of Se and one atom of O.
How many atoms are there in 61.7 g of selenium?
1 mol of sulfur contains 6.02 x 1023 molecules (avogadro constant). In one molecule of sulfur, S8, there are 8 sulfur atoms. Thus, number of atooms in 7.20 moles of sulfur = 8 x 7.20 x 6.02 x 1023 = 3.47 x 1025 Note: Sulfur does not usually exist in a monatomic form but instead forms cyclic octatomic molecules with molecular formula S8.
How do you draw the Lewis structure for the Se and 2 H atoms?
To draw the Lewis structure for selenium (Se) and two hydrogen (H) atoms, start by determining the total number of valence electrons: Se has 6 valence electrons, and each H has 1, giving a total of 8 valence electrons. Place the Se atom in the center and bond it to the two H atoms, using 2 electrons for each bond. After forming the two H-Se bonds, distribute the remaining 4 electrons around Se to satisfy its octet, typically showing two lone pairs. The final structure will have Se in the center with two H atoms bonded to it and two lone pairs on Se.
