Multiply 0.58 by Avogadro's number, which is 6.02 x 10^23.
To convert grams of selenium (Se) to moles, divide the given mass by the molar mass of selenium. The molar mass of selenium is approximately 78.97 g/mol. ( \dfrac{2.76 : g}{78.97 : g/mol} = 0.035 : mol : Se)
The element with the most moles of atoms in a 1.0 gram sample would be Mo (Molybdenum) as it has the highest molar mass among the given elements (95.94 g/mol). This means that 1.0 gram of Mo would contain the most moles of atoms compared to Se (Selenium), Na (Sodium), and Br (Bromine).
The Lewis dot structure for SeTe3 will have selenium (Se) in the center bonded to three tellurium (Te) atoms. Each Te atom will be bonded to the Se atom by a single bond, and there will be lone pairs on the tellurium atoms to satisfy their octet.
The chemical formula for aluminum selenide is Al2Se3. This is an ionic compound, so it is shown with 2 Al 2+ + 3 [Se] 2-. Around the Se are dot pairs on all four sides showing the complete transfer of electrons from the Al to the Se atoms.
The chemical formula for silver selenide is Ag₂Se. It is composed of two atoms of silver (Ag) and one atom of selenium (Se) in the compound.
Atomic mass Se = 78.96. So, atoms Se in 80.7g would be 80.7 g x 1mol/78.96g x 6.02x10^23atoms/mol = 6.15x10^23 atoms
To determine the mass, you need to first find the molar mass of selenium, which is 78.971 g/mol. Then, divide the number of atoms by Avogadro's number to find the number of moles (5.56x10^24 atoms / 6.022x10^23 atoms/mol). Finally, multiply the number of moles by the molar mass to get the mass in grams (moles x molar mass).
The answer about SE is: symbol equation
To convert grams of selenium (Se) to moles, divide the given mass by the molar mass of selenium. The molar mass of selenium is approximately 78.97 g/mol. ( \dfrac{2.76 : g}{78.97 : g/mol} = 0.035 : mol : Se)
1.9 mol Se ( 78.96 grams/1mol Se ) = 150.024 grams
A sample of Se weighs 20.5 grams. Will a sample of V that contains the same number of atoms weigh more or less than 20.5 grams? (more, less): _______Calculate the mass of a sample of V that contains the same number of atoms. _______ grams of VAnswer:Since the atomic weight of V is smaller than the atomic weight of Se, each atom will have a smallermass, and the sample will weigh less.Since the same number of moles will contain the same number of atoms, regardless of the element, it is only necessary to find the number of moles of Se in the 20.5 gram sample, and then to find the mass of the same number of moles of V.The atomic weight of Se is 79.0 g/mol1. Convert grams of Se to moles of Se:moles Se= 20.5 g Se1 mol = 0.260 mol Se79.0 gMultiply by moles per gram. Grams cancel out.The atomic weight of V is 50.9 g/mol2. To convert 0.260 moles of V to grams of V:grams V = 0.260 mol V50.9 g = 13.2 g V1 molMultiply by grams per mole. Moles cancel out.
The element with the most moles of atoms in a 1.0 gram sample would be Mo (Molybdenum) as it has the highest molar mass among the given elements (95.94 g/mol). This means that 1.0 gram of Mo would contain the most moles of atoms compared to Se (Selenium), Na (Sodium), and Br (Bromine).
One atom of Se and one atom of O.
1 mol of sulfur contains 6.02 x 1023 molecules (avogadro constant). In one molecule of sulfur, S8, there are 8 sulfur atoms. Thus, number of atooms in 7.20 moles of sulfur = 8 x 7.20 x 6.02 x 1023 = 3.47 x 1025 Note: Sulfur does not usually exist in a monatomic form but instead forms cyclic octatomic molecules with molecular formula S8.
se and sometimes gain electrons. Atoms with eight valence electrons do not easily lose electrons
The Lewis dot structure for SeTe3 will have selenium (Se) in the center bonded to three tellurium (Te) atoms. Each Te atom will be bonded to the Se atom by a single bond, and there will be lone pairs on the tellurium atoms to satisfy their octet.
se and sometimes gain electrons. Atoms with eight valence electrons do not easily lose electrons