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12.54 (g O2) / 2*15.99 (g/mol O2) = 0.3921 mol O2 -->

0.3921 (mol O2) * 6.022*1023 (molecules O2)/(molO2) =

= 2.361*1023 molecules O2

= 4.723*1023 atoms O

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How many atoms are in 50.0g of diatomic oxygen?

We first need to determine the number of moles in 50.0g of diatomic oxygen using its molar mass. The molar mass of O2 is 32.0 g/mol. Therefore, 50.0g of O2 is equivalent to 50.0g / 32.0 g/mol = 1.56 mol. Since there are 2 atoms of oxygen in every molecule of O2, we can calculate the number of atoms in 50.0g of O2 by multiplying the number of moles by Avogadro's number: 1.56 mol * 6.022 x 10^23 atoms/mol = 9.33 x 10^23 atoms.


How many chromium atoms and how many oxygen atoms are indicated on the right side of this balanced chemical equation 4 Crs 3 O2g 2 Cr2O3g?

In the balanced chemical equation 4 Cr(s) + 3 O2(g) → 2 Cr2O3(g), there are a total of 6 chromium atoms (2 from Cr and 4 from Cr2O3) and 6 oxygen atoms (6 from O2 and 3 from Cr2O3) on the right side of the equation.


How many moles in 150.0 g O2?

To find the number of moles in 150.0 g of O2, first calculate the molar mass of O2, which is 32.0 g/mol (16 g/mol for each oxygen atom). Then, divide the given mass by the molar mass to get the number of moles: 150.0 g / 32.0 g/mol = 4.69 moles of O2.


How many grams of oxygen are needed to react with 21.0 g of Mg?

The balanced chemical equation for the reaction between Mg and O2 is 2Mg + O2 -> 2MgO. This equation shows that 1 mole of Mg reacts with 1 mole of O2. The molar mass of O2 is 32 g/mol. Therefore, 21.0 g of Mg will react with 16.0 g of O2, which is 0.5 moles of O2.


How many grams of oxygen form when each quantity of reactant completely reacts. 2 KClO3 (s) plus 2 KCl(s) 3O2 (g)?

The balanced chemical reaction equation says that you get 3 moles of O2.m O2 = ( n O2 ) ( M O2 )m O2 = ( 3 mol O2 ) ( 32.00 g O2 / mol O2 = 96 g O2

Related Questions

How many moles of oxygen atoms are in 2.53 g of calcium hydroxide?

The answer is 0,068 mol (for O not for O2).


What is the formulae of oxygen?

The chemical formula for oxygen is O2, which means it is made up of two oxygen atoms bonded together.


How many atoms are in 50.0g of diatomic oxygen?

We first need to determine the number of moles in 50.0g of diatomic oxygen using its molar mass. The molar mass of O2 is 32.0 g/mol. Therefore, 50.0g of O2 is equivalent to 50.0g / 32.0 g/mol = 1.56 mol. Since there are 2 atoms of oxygen in every molecule of O2, we can calculate the number of atoms in 50.0g of O2 by multiplying the number of moles by Avogadro's number: 1.56 mol * 6.022 x 10^23 atoms/mol = 9.33 x 10^23 atoms.


How many chromium atoms and how many oxygen atoms are indicated on the right side of this balanced chemical equation 4 Crs 3 O2g 2 Cr2O3g?

In the balanced chemical equation 4 Cr(s) + 3 O2(g) → 2 Cr2O3(g), there are a total of 6 chromium atoms (2 from Cr and 4 from Cr2O3) and 6 oxygen atoms (6 from O2 and 3 from Cr2O3) on the right side of the equation.


How many moles of oxygen atoms combine with 127 g of copper?

One mole of oxigen (O2-the diatomic molecule) is needed for 127,092 g copper to form CuO.


How many moles in 150.0 g O2?

To find the number of moles in 150.0 g of O2, first calculate the molar mass of O2, which is 32.0 g/mol (16 g/mol for each oxygen atom). Then, divide the given mass by the molar mass to get the number of moles: 150.0 g / 32.0 g/mol = 4.69 moles of O2.


How many atoms of O2 are in a 1.76sample of CO2?

1.76 grams CO2 (1 mole CO2/44.01 grams)(2 mole O/1 mole CO2)(6.022 X 10^23/1 mole O2) = 4.82 X 10^22 atoms of oxygen gas


Calculate the number of atoms of O contained in 16.0 pounds of O?

To calculate the number of oxygen atoms in 16.0 pounds of oxygen, first convert 16.0 pounds to grams (1 pound ≈ 453.592 grams). Then, calculate the number of moles of oxygen using the molar mass of oxygen (16.00 g/mol). Finally, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of oxygen atoms.


How do you figure out 3.2 moles of o2?

The mass of 3.2 moles O2? The atoms in 3.2 moles O2 Could be other things, I guess, but I will do these two. 3.2 moles O2 (32 grams/1 mole O2) = 102.4 grams of gaseous oxygen -------------------------------------------- 3.2 mole O2 (6.022 X 1023/1 mole O2) = 1.9 X 1024 atoms of gaseous oxygen --------------------------------------------------


How many grams of oxygen are needed to react with 21.0 g of Mg?

The balanced chemical equation for the reaction between Mg and O2 is 2Mg + O2 -> 2MgO. This equation shows that 1 mole of Mg reacts with 1 mole of O2. The molar mass of O2 is 32 g/mol. Therefore, 21.0 g of Mg will react with 16.0 g of O2, which is 0.5 moles of O2.


How many atoms of oxygen are contained in each what How many oxygen atoms in 21 g of O2 How many oxygen atoms in 0.812 moles MgO How many oxygen atoms in 3.2 x 1022 molecules of C6H12O6?

a. number of atoms = mass / molar mass x avagadros number 21/16x6.02x1023=7.9x1023 atoms b. number of atoms = moles x avagadros number 0.812x6.02x1023=4.89x1023 atoms as there is 1 O atom in each molecule of MgO, there are 4.89x1023 atoms of Oxygen. c. if there are 3.2x1022 molecules and 6 oxygen atoms in each molecule then: (3.2x1022)x6=1.92x1023 Oxygen atoms.


How many atoms are in 49.1740 g of zirconium?

49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms