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Use the ideal gas equation to get moles of water vapor.

PV = nRT

(1 atm)(131.97 L) = n(0.08206 L*atm/mol*K)(298.15 K)

= 5.3939 moles H2O (6.022 X 10^23/1 mole H2O)

= 3.2482 X 10^24 atoms of water vapor

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Q: How many atoms are in 131.97 liters of water vapor at STP?
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